清空筛选条件
清空筛选条件

Matrix to Scalar Problem

2 次查看（过去 30 天）
Nahuel
Nahuel 2023-9-6
评论： MarKf 2023-9-6
Hi everyone,
I have a problem in the line 10, that it is ofcourse cause of the multiplication between a Matrix and a Scalar. But I do not find how to solve it.
  1. t=0:3:60;%seconds
  2. Pos0=0;%position
  3. Vel0=0;%velocity
  4. W=6.28;%frecuency
  5. e=2.71828;%Euler
  6. Damp_Coef=0;
  7. Wd=W*(1-Damp_Coef^2)^0.5;
  8. alfa=atan((Vel0+Pos0*Damp_Coef*W)/(Wd*Pos0));
  9. C=(Pos0^2+((Vel0+Pos0*Damp_Coef*W)^2)/Wd^0.5)^(0.5);
  10. x=C*e^(-Damp_Coef*W*t)*cos(Wd*t-alfa);
  11. figure
  12. plot(t,x)
  13. xlabel('time,s')
  14. ylabel('x(t)')
  15. legend('NANU')
  16. title('lets see')
  2 个评论
John D'Errico
John D'Errico 2023-9-6
编辑：John D'Errico 2023-9-6
Please don't number those lines. That makes it impossible to copy your code. Why do you want to make it more difficult to get help? Just making the line in question bold faced as you did was certainly sufficient.
MarKf
MarKf 2023-9-6
fortuantely it is just a numbered list, so it is easy to copy actually... but yes interesting appoach, bold/underlined or even code %<-- issue here would have worked

请先登录，再进行评论。

请先登录，再回答此问题。

回答（3 个）

Les Beckham
Les Beckham 2023-9-6
Ran in:
t=0:3:60;%seconds
Pos0=1;%position <<< Pos0 can't be zero since you divide by Wd*Pos0 when calculating alfa
Vel0=0;%velocity
W=6.28;%frecuency
e=2.71828;%Euler
Damp_Coef=0.02; % <<< Damp_Coef can't be zero
Wd=W*(1-Damp_Coef^2)^0.5;
alfa=atan((Vel0+Pos0*Damp_Coef*W)/(Wd*Pos0));
C=(Pos0^2+((Vel0+Pos0*Damp_Coef*W)^2)/Wd^0.5)^(0.5);
x=C*exp(-Damp_Coef*W.*t).*cos(Wd.*t-alfa);
% ^ use exp instead of e^ and use element-wise multiplies: .* instead of *
figure
plot(t,x)
grid on
xlabel('time,s')
ylabel('x(t)')
legend('NANU')
title('lets see')
Torsten
Torsten 2023-9-6
x=C*exp(-Damp_Coef*W*t).*cos(Wd*t-alfa);
MarKf
MarKf 2023-9-6
Ran in:
Use a dot "." before an element-wise operation, that is also to multiply, divide, raise etc a scalar value to each of the element of a vector/matrix. Example below, tho not sure that's what you meant to do.
t=0:3:60;%seconds
Pos0=0;%position
Vel0=0;%velocity
W=6.28;%frecuency
e=2.71828;%Euler
Damp_Coef=0;
Wd=W*(1-Damp_Coef^2)^0.5;
alfa=atan((Vel0+Pos0*Damp_Coef*W)/(Wd*Pos0));
C=(Pos0^2+((Vel0+Pos0*Damp_Coef*W)^2)/Wd^0.5)^(0.5);
x=C*e.^(-Damp_Coef*W*t).*cos(Wd*t-alfa);
figure
plot(t,x)
xlabel('time,s')
ylabel('x(t)')
legend('NANU')
title('lets see')

类别

在 Help Center 和 File Exchange 中查找有关 MATLAB 的更多信息

标签

产品


版本

R2023a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by