Why am I getting a parse error trying to put this function in MATLAB?

Question

Isaac Smith 2023-9-6

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/2017736-why-am-i-getting-a-parse-error-trying-to-put-this-function-in-matlab

回答： Mrutyunjaya Hiremath 2023-9-6

I'm trying to put this function into MATLAB: e^x + x^2 − x − 4

When I do this I get a parse error at exp and I don't understand why: fx = @x exp(x) + x^2 - x - 4

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

请先登录，再进行评论。

请先登录，再回答此问题。

Answer 1

Walter Roberson 2023-9-6

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/2017736-why-am-i-getting-a-parse-error-trying-to-put-this-function-in-matlab#answer_1303556

在 MATLAB Online 中打开

fx = @x exp(x) + x^2 - x - 4

In MATLAB, @ followed by a name is a request to create a function handle to a function with the given name. So @x is a request to create a function handle to a function named x

After that, you do not have an kind of operator or separator before you encounter the next term, exp(x) .

I suspect that what you wanted was

fx = @(x) exp(x) + x^2 - x - 4

The () are an important part of the syntax.

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

请先登录，再进行评论。

Answer 2

Mrutyunjaya Hiremath 2023-9-6

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/2017736-why-am-i-getting-a-parse-error-trying-to-put-this-function-in-matlab#answer_1303561

在 MATLAB Online 中打开

The issue you're encountering is because you have a syntax error in your MATLAB function declaration. You should define your function using an anonymous function handle properly.

Here's the correct way to define your function:

fx = @(x) exp(x) + x^2 - x - 4;

In MATLAB, you create an anonymous function handle using @ and then specify the variable (x in this case) inside the parentheses. This allows you to use x as the input to your function.