trying to loop for transfer function plots into single figure
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Parameters========================
Km1 = 0.01;
Km2 = 0.02257;
Km3 = 0.04;
Rm = 2.093;
b = 0.0000262;
t = 0.069;
T=0:0.0001:4;
========================================
something I tried, but It didnt work
for i :1:3
K(i) = Km(i)/(Rm*b+Km(i)^2);
oltf(i)=tf([K(i)],[t,(i)]);
step(i)=step(oltf(i),T);
plot(T, step(i),'r');
end
trying to fit all three plots into one figure
Thank you!!
1 个评论
VINAYAK LUHA
2023-9-7
编辑：VINAYAK LUHA
2023-9-7
The "hold on" command may help, find its documentation in the following link https://in.mathworks.com/help/matlab/ref/hold.html
采纳的回答
%Do not name variables dynamically
%defining them in an array and using indexing is a much better option
Km = [0.01 0.02257 0.04];
Rm = 2.093;
b = 0.0000262;
t = 0.069;
T = 0:0.0001:4;
%Defining K via vectorization
K = Km./(Rm.*b+Km.^2);
%Initialise a figure and use hold on to retain plots on the same axes
figure
hold on
for i =1:3
oltf = tf([K(i)],[t,(i)]);
step(oltf,T)
%%It's not a good idea to use function names as variables names
%step(i)=step(oltf(i),T);
%%No need to use the plot command, as the step command itself outputs a plot
%plot(T, st(i),'r')
end
hold off
4 个评论
Young Lee
2023-9-7
Hi @Young Lee
@Dyuman Joshi didn't make any mistakes in the code because he merely duplicated the transfer function from your original code. However, based on your screenshot, I would like to suggest that the correct transfer function should be:
It's perfectly fine to notify him about the issue you had.
Km1 = 0.01;
Km2 = 0.02257;
Km3 = 0.04;
Km = [Km1 Km2 Km3];
Rm = 2.093;
b = 0.0000262;
t = 0.069;
T = 0:0.0001:4;
for i = 1:3
K = Km(i)/(Rm*b + Km(i)^2);
den = [t, 1]; % <-- fix denominator here
oltf = tf(K, den);
step(oltf, T), hold on
end
grid on
hold off
Young Lee
2023-9-8
Sam Chak
2023-9-8
@Young Lee, You are welcome!
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