How to code NESTED CYCLES

f=[3 6 3 9]
b=[5 8 10 12]
a is a function with parameter f and b!
for l=1:numel(b)
for i=1:numel(f)
a(f(i),b(l))
end
end
but this is a problem:
if b is empty the function won't loop me with "f"

 采纳的回答

I would set the empty array to 1 (so that it iterates one time only) and be done with it —
a = @(x,y) [x y];
f = [3 6 3 9]; % Neither Empty
b = [5 8 10 12];
if isempty(f)
f = NaN;
elseif isempty(b)
b = NaN;
end
for l=1:numel(b)
for i=1:numel(f)
q = a(f(i),b(l))
end
end
q = 1×2
3 5
q = 1×2
6 5
q = 1×2
3 5
q = 1×2
9 5
q = 1×2
3 8
q = 1×2
6 8
q = 1×2
3 8
q = 1×2
9 8
q = 1×2
3 10
q = 1×2
6 10
q = 1×2
3 10
q = 1×2
9 10
q = 1×2
3 12
q = 1×2
6 12
q = 1×2
3 12
q = 1×2
9 12
f = []; % 'f' Empty
b = [5 8 10 12];
if isempty(f)
f = NaN;
elseif isempty(b)
b = NaN;
end
for l=1:numel(b)
for i=1:numel(f)
q = a(f(i),b(l))
end
end
q = 1×2
NaN 5
q = 1×2
NaN 8
q = 1×2
NaN 10
q = 1×2
NaN 12
f = [3 6 3 9]; % 'b' Empty
b = [];
if isempty(f)
f = NaN;
elseif isempty(b)
b = NaN;
end
for l=1:numel(b)
for i=1:numel(f)
q = a(f(i),b(l))
end
end
q = 1×2
3 NaN
q = 1×2
6 NaN
q = 1×2
3 NaN
q = 1×2
9 NaN
The ‘default’ value (here ‘NaN’) can be any value that makes sense in the context of whatever ‘a’ does. If a given argument is added, then set it to the identity element for that operation, so if it is added set it to 0 if the associated vector is empty, if it is multiplied, set it to 1.
.

更多回答(2 个)

Reverse the 2 loops, then it loops on f
f=[3 6 3 9]
f = 1×4
3 6 3 9
b=[]
b = []
for i=1:numel(f)
f(i)
for l=1:numel(b)
a(f(i),b(l))
end
end
ans = 3
ans = 6
ans = 3
ans = 9

2 个评论

I wrote the code in general but I don't know which array is empty..it can be f or b
Split in three loops if you have to
for i=1:numel(f)
for l=1:numel(b)
% ... do something with both f(i) and b(l)
a(f(i),b(l))
end
end
for i=1:numel(f)
% ... do something with f(i) ALONE
end
for l=1:numel(b)
% ... do something with b(l) ALONE
end

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Check them in advance:
if isempty(b)
% What to do
return;
end
if isempty(f)
% What to do
return;
end
for l=1:numel(b)
for i=1:numel(f)
something = a(f(i),b(l))
end
end

2 个评论

if b=[] it don't execute cycle for
b=[];
f=[3 4 5];
if isempty(b)
% What to do
return;
end
if isempty(f)
% What to do
return;
end
for l=1:numel(b)
for i=1:numel(f)
fprintf("execure cycle \n");
end
end
Correct. Why would you want to continue if one is empty? If you do you'll just get an error. If you can "fix" the situation, do so inside the if -- for example Star set them to nan instead. If you can't fix the situation, you should just exit the code after alerting the user.

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