how to assign rank to each row?

5 次查看(过去 30 天)
I have a matrix as follows:
A=[1 4;
1 4;
4 1;
4 1;
2 2;
2 3;
2 3;
3 2;
3 3];
I want to have another matrix like this-
B=[1;1;2;2;3;4;4;5;6];
Basically, I want to check each row and increase the corresponding value by 1 if iot does not matches with the preceding one. if it matche with the preceding one, I want to keep it as before.
How can I do this?
  1 个评论
Torsten
Torsten 2023-9-13
编辑:Torsten 2023-9-13
For beginners, a for loop over the rows of A, inside the loop: a comparison of row i with row i-1 and an if-statement that adds 1 to element B(i-1) to get element B(i) if the two rows are not equal and that sets B(i) to B(i-1) if they are equal.

请先登录,再进行评论。

采纳的回答

Stephen23
Stephen23 2023-9-13
A = [1,4;1,4;4,1;4,1;2,2;2,3;2,3;3,2;3,3]
A = 9×2
1 4 1 4 4 1 4 1 2 2 2 3 2 3 3 2 3 3
B = cumsum([1;any(diff(A,1,1),2)])
B = 9×1
1 1 2 2 3 4 4 5 6
  2 个评论
Les Beckham
Les Beckham 2023-9-13
Note that diff(A,1,1) is the same as diff(A) so this can be simplified as
A = [1,4;1,4;4,1;4,1;2,2;2,3;2,3;3,2;3,3]
A = 9×2
1 4 1 4 4 1 4 1 2 2 2 3 2 3 3 2 3 3
B = cumsum([1;any(diff(A),2)])
B = 9×1
1 1 2 2 3 4 4 5 6
Stephen23
Stephen23 2023-9-13
编辑:Stephen23 2023-9-13
"Note that diff(A,1,1) is the same as diff(A) so this can be simplified as"
Not quite. Consider what happens if one day A happens to have exactly one row... my code still works correctly for any size of matrix A, whereas not specifying the dimension is a latent bug.
For the same reason experienced MATLAB users often prefer to specify the (optional) dimension with many common functions e.g. MAX, MIN, MEAN, etc. when used with non-vector data.

请先登录,再进行评论。

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Logical 的更多信息

标签

产品


版本

R2023a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by