Random number generate in an interval

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Hi community,
I would like to generate random number in the follow distribuition: Normal, Gamma and Weibull.
Amount of data required: 5000 numbers at interval [a,b]
At the example, it was used the follow code:
A = linspace(0,1,5000)
sr = size(A)
b = normrnd(27.5,15.73,sr)
plot(b)
Its works, however, the valid interval to generate was [1,54]
Can us help me, please?
Yours faithfully
  7 个评论
Walter Roberson
Walter Roberson 2023-9-14
Right, different interpretations of what "clipping" means in the context.
format long g
b = normrnd(27.5,15.73,[1 500000]);
out_of_range = (b < 1) | (b > 54);
mean(out_of_range) * 100
ans =
9.195
so over 9% of the samples are outside of the target range

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回答(2 个)

the cyclist
the cyclist 2023-9-14
编辑:the cyclist 2023-9-14
A normal distribution, by definition, has support from negative infinity to positive infinity. You cannot have both a normal distribution and a finite range.
You can use the truncate function to create a truncated normal distribution object, and draw values from that. (See the second example on that page.) Is that what you want?

Bruno Luong
Bruno Luong 2023-9-14
编辑:Bruno Luong 2023-9-15
This doesn't need stat toolbox.
sigma = 15.73;
mu = 27.5;
interval = [1 54];
n = [1, 5000000];
X = TruncatedGaussian(-sigma,interval-mu,n) + mu;
histogram(X)

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