0 个投票

I used the following code, and you can see that in the second row of the fourth column, the result is zero and not NaN; it should be NaN as the result.
%
soma_total = nan(3, 4);
data1 = [nan nan 1 2; 1 2 nan nan; 1 2 nan nan];
data2 = [5 5 nan nan; 2 1 1 nan; nan nan 1 1];
%
result = nansum(cat(3, soma_total, data1, data2), 3);
%
disp(result);
The result was:
[5 5 1 2;
3 3 1 0;
1 2 1 1]
The result should be:
[5 5 1 2;
3 3 1 NaN;
1 2 1 1]
Does anyone have an idea to solve this?

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Dyuman Joshi
Dyuman Joshi 2023-9-16
编辑：Dyuman Joshi 2023-9-16
Ran in:

0 个投票

Ran in:
nansum does not do what you are expecting it to do. Also, using nansum() is not recommended as you can see from its documentation page. Use sum instead -
Here's a workaround -
%
soma_total = nan(3, 4);
data1 = [nan nan 1 2; 1 2 nan nan; 1 2 nan nan];
data2 = [5 5 nan nan; 2 1 1 nan; nan nan 1 1];
%Dimension to operate on
dim = 3;
%defining the array
arr = cat(dim, soma_total, data1, data2);
%Finding indices for all elements which are NaN corresponding to the "dim" dimension
idx = all(isnan(arr),dim)
idx = 3×4 logical array
0 0 0 0 0 0 0 1 0 0 0 0
%If you want to use nansum instead, use this command
%result = nansum(arr,dim)
result = sum(arr,dim,'omitnan')
result = 3×4
5 5 1 2 3 3 1 0 1 2 1 1
%Converting the respective values back to NaN
result(idx) = NaN
result = 3×4
5 5 1 2 3 3 1 NaN 1 2 1 1

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