how to use varagin with parameter

1 次查看(过去 30 天)
piero
piero 2023-9-18
编辑: Matt J 2023-9-19
function definedAndVariableNumInputs(X,Y,varargin)
disp("Total number of input arguments: " + nargin)
formatSpec = "Size of varargin cell array: %dx%d";
str = compose(formatSpec,size(varargin));
disp(str)
if varargin{1}=="f"
??
end
varargin{2}=="b"
??
end
acceptVariableNumInputs(3,4,"b")
hi,I want to call the function with additional parameters
If I pass the parameter called "f" I want to pass it the value 3
If I pass the "b" parameter I want to pass the value 5
(it's an example)
Now with varagin I can see the values I pass but not what they refer to... how to do this?
Example I just want to pass it the value of parameter "b" ..
How does the function understand that the only parameter passed refers to "b"?
  1 个评论
Voss
Voss 2023-9-19
It's not clear what you are trying to do.
Can you write down a few examples of how this function would be called and how it should interpret the input arguments in each case?

请先登录,再进行评论。

回答(2 个)

Matt J
Matt J 2023-9-19
编辑:Matt J 2023-9-19
Perhaps this is what you're looking for:
opts=myfunc(f=3)
opts = struct with fields:
f: 3 b: []
opts=myfunc(b=5)
opts = struct with fields:
f: [] b: 5
opts=myfunc(f=3,b=5)
opts = struct with fields:
f: 3 b: 5
function opts=myfunc(opts)
arguments
opts.f=[];
opts.b=[];
end
end

Matt J
Matt J 2023-9-19
编辑:Matt J 2023-9-19
Another possibility:
out=definedAndVariableNumInputs(10,20,f=3)
out = struct with fields:
X: 10 Y: 20 f: 3 b: []
function out=definedAndVariableNumInputs(X,Y,varargin)
out.X=X;
out.Y=Y;
out.f=[];
out.b=[];
settings=struct(varargin{:});
for f=string(fieldnames(settings));
out.(f)=settings.(f);
end
end

类别

Help CenterFile Exchange 中查找有关 Search Path 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by