how to use varagin with parameter

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piero
piero 2023-9-18
编辑： Matt J 2023-9-19
function definedAndVariableNumInputs(X,Y,varargin)
disp("Total number of input arguments: " + nargin)
formatSpec = "Size of varargin cell array: %dx%d";
str = compose(formatSpec,size(varargin));
disp(str)
if varargin{1}=="f"
??
end
varargin{2}=="b"
??
end
acceptVariableNumInputs(3,4,"b")
hi,I want to call the function with additional parameters
If I pass the parameter called "f" I want to pass it the value 3
If I pass the "b" parameter I want to pass the value 5
(it's an example)
Now with varagin I can see the values I pass but not what they refer to... how to do this?
Example I just want to pass it the value of parameter "b" ..
How does the function understand that the only parameter passed refers to "b"?
  1 个评论
Voss
Voss 2023-9-19
It's not clear what you are trying to do.
Can you write down a few examples of how this function would be called and how it should interpret the input arguments in each case?

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回答（2 个）

Matt J
Matt J 2023-9-19
编辑：Matt J 2023-9-19
Ran in:
Perhaps this is what you're looking for:
opts=myfunc(f=3)
opts = struct with fields:
f: 3 b: []
opts=myfunc(b=5)
opts = struct with fields:
f: [] b: 5
opts=myfunc(f=3,b=5)
opts = struct with fields:
f: 3 b: 5
function opts=myfunc(opts)
arguments
opts.f=[];
opts.b=[];
end
end
Matt J
Matt J 2023-9-19
编辑：Matt J 2023-9-19
Ran in:
Another possibility:
out=definedAndVariableNumInputs(10,20,f=3)
out = struct with fields:
X: 10 Y: 20 f: 3 b: []
function out=definedAndVariableNumInputs(X,Y,varargin)
out.X=X;
out.Y=Y;
out.f=[];
out.b=[];
settings=struct(varargin{:});
for f=string(fieldnames(settings));
out.(f)=settings.(f);
end
end

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