error to assign string in field struct's

Question

piero 2023-9-23

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/2024937-error-to-assign-string-in-field-struct-s

评论： piero 2023-9-24

采纳的回答： Walter Roberson

>> SlippSource(2)

ans =

categorical

From instrument

Sis(:).Slipp

ans =

'From strategy'

ans =

'From strategy'

ans =

'From strategy'

>> class(Sis)

ans =

'struct'

>> size(Sis)

ans =

1 73

>> [Sis.SlippSource]=SlippSource(2)

Error using ()

Too many output arguments.

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

请先登录，再进行评论。

请先登录，再回答此问题。

Answer 1

Walter Roberson 2023-9-23

1
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/2024937-error-to-assign-string-in-field-struct-s#answer_1316812

在 MATLAB Online 中打开

Compare:

Sis(73).Slipp = 'example';
[Sis.SlippSource] = testfun();
Error using solution>testfun
Too many output arguments.
function output = testfun()
   output = 123;
end

2 个评论
显示无隐藏无

Walter Roberson 2023-9-23

在 MATLAB Online 中打开

Sis(73).Slipp = 'example';
[Sis.SlippSource] = deal(testfun());
whos Sis
  Name      Size            Bytes  Class     Attributes

  Sis       1x73             8998  struct              
function output = testfun()
   output = 123;
end

Your Sis is a 1 x 73 struct. When you use [Sis.SlippSource] = SlippSource(2) then SlippSource(2) would have to be an expression that returns at least 73 output arguments.

Remember, when you have a non-scalar struct A then [A.B]=C is equivalent to coding [A(1).B, A(2).B, A(3).B, ... A(end).B] = C; which requires that C has enough outputs.

If you want to assign the same value to a particular field in each entry in the struct, then use deal like I show here.

piero 2023-9-24