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How to get this equation to plot

9 次查看（过去 30 天）
Jon
Jon 2023-9-25
评论： Torsten 2023-9-25
I am trying to plot this equation and matlab thinks it is matrix multiplication when it is not. I have included my code. I also included a screen shot of what matlab is telling me.
%x1'=10e^-3t*-sin(200t)+2e^-3t*cos(200t)
%x2'=-10e^-3t*cos(200t)+2e^-3t*sin(200t)
tspan=[-10 10];
x1=10*exp(-3*t)*(-sin(200*t))+2*exp(-3*t)*cos(200*t);
x2=-10*exp(-3*t)*cos(200*t)+2*exp(-3*t)*sin(200*t);
figure
hold on
fplot(x1,tspan,'r');
fplot(x2,tspan,'b');
xlim([0 1]);
ylim([-10 10]);
xlabel('Time');
ylabel('Solutions')
title('{x1(t)}, {x2(t)}');
grid on
hold off
  1 个评论
Torsten
Torsten 2023-9-25
You are given the derivatives x1' and x2' of x1 and x2. You need to apply MATLAB's "int" to determine their antiderivatives first before plotting.

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采纳的回答

Voss
Voss 2023-9-25
Ran in:
Use .* for element-wise multiplication, and if you want to use fplot then x1 and x2 should be function handles (I've added "@(t)" at the beginning of their definitions to do so).
%x1'=10e^-3t*-sin(200t)+2e^-3t*cos(200t)
%x2'=-10e^-3t*cos(200t)+2e^-3t*sin(200t)
tspan=[-10 10];
x1=@(t)10*exp(-3*t).*(-sin(200*t))+2*exp(-3*t).*cos(200*t);
x2=@(t)-10*exp(-3*t).*cos(200*t)+2*exp(-3*t).*sin(200*t);
figure
hold on
fplot(x1,tspan,'r');
fplot(x2,tspan,'b');
xlim([0 1]);
ylim([-10 10]);
xlabel('Time');
ylabel('Solutions')
title('{x1(t)}, {x2(t)}');
grid on
hold off

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