I want to solve this system of differential equations. Is there any code that can solve this?

1 次查看(过去 30 天)
I am trying to solve this system of differential equations using numerical analysis. However, I couldn't find any Matlab code to solve this.
Is there a code that can numerically analyze this type of equation?
I = 0.000122144; %kgm^2
m = 0.19744; %kg
g = 9.80665; %m/s^2
R = 0.035; %m
s = 0.090757; %rad
r = -0.011515; %m
M = 0.029244; %kg
k = 15.36;
A = 0.011065331; %m^2
syms x(t) y(t)
ode1 = I * diff(y, 2) == -m * sqrt(g^2 + R^2 * (diff(x, 2))^2 - 2 * g * R * diff(x, 2) * sin(s)) * r * sin(s + y - atan(R * diff(x, 2) * cos(s) / (g - R * diff(x, 2) * sin(s)))) - k * R * A * (diff(y) - diff(x));
ode2 = 2 * M * R * diff(x, 2) == (M + m) * g * sin(s) - m * r * (sin(y) * (diff(y)^2) - cos(x) * (diff(x)^2));
condition1 = x(0) == 0;
condition2 = y(0) == 0;
condition3 = diff(x) == 0;
condition4 = diff(y) == 0;

采纳的回答

Torsten
Torsten 2023-9-29
编辑:Torsten 2023-9-29
Note that there is a discrepancy between your code and your graphics for the second ode. I took the version from the graphics ( which worked better for ode15i :-) )
y0 = [0 0 0 0];
yp0 = [0 0 0 0];
t0 = 0;
tspan = [t0,0.25];
[y0_new,yp0_new] = decic(@f,t0,y0,[1 1 1 1],yp0,[0 0 0 0])
y0_new = 4×1
0 0 0 0
yp0_new = 4×1
0 0 -172.0836 289.5405
sol = ode15i(@f,tspan,y0_new,yp0_new,odeset('RelTol',1e-8,'AbsTol',1e-8));
figure(1)
plot(sol.x,[sol.y(1,:);sol.y(2,:)])
[y,yp] = deval(sol,sol.x);
for i = 1:numel(sol.x)
res(i,:) = f(sol.x(i),y(:,i),yp(:,i));
end
figure(2)
plot(sol.x,[res(:,3),res(:,4)])
function res = f(t,y,yp)
I = 0.000122144; %kgm^2
m = 0.19744; %kg
g = 9.80665; %m/s^2
R = 0.035; %m
s = 0.090757; %rad
r = -0.011515; %m
M = 0.029244; %kg
k = 15.36;
A = 0.011065331; %m^2
res = zeros(4,1);
res(1) = yp(1) - y(3);
res(2) = yp(2) - y(4);
res(3) = I*yp(3) - (-m * sqrt(g^2 + R^2 * yp(4)^2 - 2 * g * R * yp(4) * sin(s)) * r * sin(s + y(1) - atan(R * yp(4) * cos(s) / (g - R * yp(4) * sin(s)))) - k * R * A * (y(3) - y(4)));
res(4) = 2 * M * R * yp(4) -( (M + m) * g * sin(s) - m * r * (sin(y(1)) * (y(3)^2) - cos(y(1)) * yp(3)));
end
  3 个评论
Torsten
Torsten 2023-9-29
编辑:Torsten 2023-9-30
Better also look at the residuals to check whether the equations are really satisfied for the given solution. I changed the code above accordingly.
Maybe the code performs more reliable with analytical Jacobians:
I = 0.000122144; %kgm^2
m = 0.19744; %kg
g = 9.80665; %m/s^2
R = 0.035; %m
s = 0.090757; %rad
r = -0.011515; %m
M = 0.029244; %kg
k = 15.36;
A = 0.011065331; %m^2
syms t
y = sym('y',[4 1]);
yp = sym('yp',[4 1]);
f(1,1) = yp(1) - y(3);
f(2,1) = yp(2) - y(4);
f(3,1) = I*yp(3) - (-m * sqrt(g^2 + R^2 * yp(4)^2 - 2 * g * R * yp(4) * sin(s)) * r * sin(s + y(1) - atan(R * yp(4) * cos(s) / (g - R * yp(4) * sin(s)))) - k * R * A * (y(3) - y(4)));
f(4,1) = 2 * M * R * yp(4) -( (M + m) * g * sin(s) - m * r * (sin(y(1)) * (y(3)^2) - cos(y(1)) * yp(3)));
Jac_y = jacobian(f,y);
Jac_yp = jacobian(f,yp);
f = matlabFunction(f,'Vars',{t,y,yp});
Jac_y = matlabFunction(Jac_y,'Vars',{t,y,yp});
Jac_yp = matlabFunction(Jac_yp,'Vars',{t,y,yp});
Jac = @(t,y,yp) deal(Jac_y(t,y,yp),Jac_yp(t,y,yp));
y0 = [0 0 0 0].';
yp0 = [0 0 0 0].';
t0 = 0;
tspan = [t0,0.25];
options = odeset('RelTol',1e-8,'AbsTol',1e-8,'Jacobian',Jac);
[y0_new,yp0_new] = decic(f,t0,y0,[1 1 1 1].',yp0,[0 0 0 0].',options)
y0_new = 4×1
0 0 0 0
yp0_new = 4×1
0 0 -172.0836 289.5405
sol = ode15i(f,tspan,y0_new,yp0_new,options);
figure(1)
plot(sol.x,[sol.y(1,:);sol.y(2,:)])
[y,yp] = deval(sol,sol.x);
for i = 1:numel(sol.x)
res(i,:) = f(sol.x(i),y(:,i),yp(:,i));
end
figure(2)
plot(sol.x,[res(:,3),res(:,4)])

请先登录,再进行评论。

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Numerical Integration and Differential Equations 的更多信息

产品

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by