Line plotting
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for yy = 1:length(overlap_peaks2)
x=overlap_peaks2(yy);
y=1:200000:1000000;
hold on;
plot(overlap_peaks2(yy),y, '-r')
end
length(overlap_peaks2) is just equal to 1
my question is why is it when i plot it, it shows up as seperate dots, how do i make it connect into a line? i am just tryign to plot x=589
采纳的回答
Walter Roberson
2011-11-3
for yy = 1:length(overlap_peaks2)
x=overlap_peaks2(yy);
y=1:200000:1000000;
hold on;
plot(repmat(x,1,length(y)),y, '-r')
end
By the way, you should also consider
for yy = 1:length(overlap_peaks2)
x=overlap_peaks2(yy);
hold on;
plot([x x],[1 1000000], '-r')
end
更多回答（1 个）
Fangjun Jiang
2011-11-3
0 个投票
If "length(overlap_peaks2) is just equal to 1", then in your code, yy will be 1 and the loop runs once. What is the length of overlap_peaks2(yy)? If it's a scalar, you are just going to get 5 dots.
Check your code again.
2 个评论
Andy
2011-11-3
Fangjun Jiang
2011-11-3
Usually x and y are two vectors with the same size in plot(x,y), such as plot(1:10,sin(1:10)). plot(1,1:10,'-r') or plot(1:10,1,'-r') still generates a plot but only shows 10 points. Even if you can use plot(repmat(1,1,10),1:10,'-r') to make it draw the line, I am not sure what the line means to you.
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