contour plot with a circular boundary

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Zeyad Zeitoun
Zeyad Zeitoun 2023-10-5
评论： Torsten 2023-10-6
I have the following code which gives me rectangular contour, I would like to chaneg it to be circular contour (boundaries), Can anyone help me please?
L = [-0.875 -0.75 -0.625 -0.5 -0.375 -0.25 -0.125 0 0.125 0.25 0.375 0.5 0.625 0.75 0.875];
r = [-0.875 -0.75 -0.625 -0.5 -0.375 -0.25 -0.125 0 0.125 0.25 0.375 0.5 0.625 0.75 0.875];
[X,Y]=meshgrid(L,r)
T=xlsread('Tempvalues (horizontal 70 psi)try.xlsx');
Z = [T(:,1),T(:,2),T(:,3),T(:,4),T(:,5),T(:,6),T(:,7),T(:,8),T(:,9),T(:,10),T(:,11),T(:,12),T(:,13),T(:,14),T(:,15)];
contourf(X,Y,Z)
pbaspect([1,1,1])
xlabel('Dimensionless axial position (z/L)')
ylabel('Dimensionless radial position (r/R)')
title('Axial velocity distribution along heated channel')

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回答（1 个）

Torsten
Torsten 2023-10-5
编辑：Torsten 2023-10-5
If you want to plot it within a circular contour, you have a 3d-plot. For a 3d-plot, you can only plot cuts in length direction with temperature as the contours.
So in short: Plotting all your data with a circular boundary is not possible - only the radial temperature distribution at a fixed length.
And I don't know what negative radial positions mean.
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Zeyad Zeitoun
Zeyad Zeitoun 2023-10-6
The temeprature is different radially because the gas is flowing inside the cylinder by natural convection heat transfer, so there is a radial temperature gradient where the hot gas layers are above the cold layers thats why I want to draw it by contour map much better than normal plotting.
I tried your code but it doesn't represent the temperature gradient in the channel. Thanks

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