Create a graph with several isolated nodes and a few links

Question

Sim 2023-10-14

0
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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/2033484-create-a-graph-with-several-isolated-nodes-and-a-few-links

评论： Sim 2023-10-16

Why I am not able to create a graph with several isolated nodes and a few links?

s = [1
     1
     1];
t = [1
     2
     3];
XY = [    1          1.5
          1.2          1.7
          1.3          1.3
          1.7          2.2
            1            2
          4.2          2.9
          3.5          2.5
          3.8          2.9
          3.8          3.2
          3.6          3.1
            3            3
          3.4          3.4
            3          2.3];
G = graph(s,t);
G.Nodes.X = XY(:,1);  G.Nodes.Y = XY(:,2);
Error using .
To assign to or create a variable in a table, the number of rows must match the height of the table.

Error in graph/subsasgn>assignToNodes (line 161)
        nodeprop = subsasgn(nodeprop, S, V);

Error in indexing (line 18)
    G = assignToNodes(G, S, V);

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Dyuman Joshi 2023-10-14

在 MATLAB Online 中打开

But there are no isolated nodes in your graph -

s = [1

1

1];

t = [1

2

3];

G = graph(s,t);

plot(G)

Sim 2023-10-16

Hi @Dyuman Joshi! Thanks for your comments! I think @Steven Lord got my point..... Sorry, I think I did not explain well my issue... :-)

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Answer 1

Steven Lord 2023-10-14

1
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/2033484-create-a-graph-with-several-isolated-nodes-and-a-few-links#answer_1333309

在 MATLAB Online 中打开

Your code would work with one minor addition, a line that adds the additional nodes to the graph that are not present in the s and t vectors you use to create the graph.

s = [1
     1
     1];
t = [1
     2
     3];
XY = [    1          1.5
          1.2          1.7
          1.3          1.3
          1.7          2.2
            1            2
          4.2          2.9
          3.5          2.5
          3.8          2.9
          3.8          3.2
          3.6          3.1
            3            3
          3.4          3.4
            3          2.3];
G = graph(s,t);
G = addnode(G, height(XY)-numnodes(G)); % Added
G.Nodes.X = XY(:,1);
G.Nodes.Y = XY(:,2);