Rotate an object based on regionprops Orientation, MinFeret and MaxFeret angles

Question

Asi 2023-10-17

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https://ww2.mathworks.cn/matlabcentral/answers/2034614-rotate-an-object-based-on-regionprops-orientation-minferet-and-maxferet-angles

评论： Walter Roberson 2023-10-18

采纳的回答： Walter Roberson

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How can I rotate an object based on regionprops Orientation, MinFeret and MaxFeret angles?

My aim is that the object and the regionprops based plotted lines will be 0 or 90 degrees.

Thanks.

Code:

close all;

clear;

clc;

I = (insertText(zeros(150,150),[0 0],'B','BoxOpacity',0,'FontSize',70,'TextColor','w'));

I = imrotate(I,15);

I = rgb2gray(I);

figure('Name','Img');

imshow(I);

I=flipud(I);

BW = imbinarize(I);

[B,L] = bwboundaries(BW,'noholes');

k=1;

st = regionprops(I,"Centroid","MajorAxisLength","Orientation","MinFeretProperties","MaxFeretProperties");

b = B{k};

c = st(k).Centroid;

yBoundary = b(:,2);

xBoundary = b(:,1);

cy = c(:,2);

cx = c(:,1);

figure('Name','Boundary and lines');

plot(yBoundary, xBoundary, 'black', 'linewidth', 2);

hlen = st.MajorAxisLength/2;

xCentre = st.Centroid(1);

yCentre = st.Centroid(2);

cosOrient = cosd(st.Orientation);

sinOrient = sind(st.Orientation);

xcoords = xCentre + hlen * [cosOrient -cosOrient];

ycoords = yCentre + hlen * [-sinOrient sinOrient];

line(xcoords, ycoords, 'Color','red');

line([st.MaxFeretCoordinates(1),st.MaxFeretCoordinates(2)],[st.MaxFeretCoordinates(3),st.MaxFeretCoordinates(4)],'Color','blue');

line([st.MinFeretCoordinates(1),st.MinFeretCoordinates(2)],[st.MinFeretCoordinates(3),st.MinFeretCoordinates(4)],'Color','green');

orientationRotImg = imrotate(I, st.Orientation-90);

figure('Name','orientationRotImg');

imshow(orientationRotImg)

MaxFeretAngleRotImg = imrotate(I, st.MaxFeretAngle-90);

figure('Name','MaxFeretAngleRotImg');

imshow(MaxFeretAngleRotImg)

MinFeretAngleRotImg = imrotate(I, st.MinFeretAngle-90);

figure('Name','MaxFeretAngleRotImg');

imshow(MinFeretAngleRotImg)

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Asi 2023-10-17

OK. So how do I rotate it to a "B normal position"?

Walter Roberson 2023-10-18

The min ferret angle and max ferret angle are not typically going to be 90 degrees from each other, so requiring that both be rotated to horizontal or vertical is not typically going to work.

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Answer 1

Walter Roberson 2023-10-17

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链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/2034614-rotate-an-object-based-on-regionprops-orientation-minferet-and-maxferet-angles#answer_1334814

移动：Matt J 2023-10-17

在 MATLAB Online 中打开

close all;

clear;

clc;

I = (insertText(zeros(150,150),[0 0],'B','BoxOpacity',0,'FontSize',70,'TextColor','w'));

I = imrotate(I,15);

I = rgb2gray(I);

figure('Name','Img');

imshow(I);

I=flipud(I);

BW = imbinarize(I);

[B,L] = bwboundaries(BW,'noholes');

k=1;

st = regionprops(I,"Centroid","MajorAxisLength","Orientation","MinFeretProperties","MaxFeretProperties");

MinFeretAngleRotImg = imrotate(I, st.MinFeretAngle);

figure('Name','MaxFeretAngleRotImg');

imshow(MinFeretAngleRotImg)

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Asi 2023-10-18

移动：Walter Roberson 2023-10-18

在 MATLAB Online 中打开

Hi,

Thanks but it seems to me that the B should be flliped.

I tried the code with another letter "A"

I = (insertText(zeros(150,150),[0 0],'A','BoxOpacity',0,'FontSize',70,'TextColor','w'));

and this us the result of MinFeretAngleRotImg = imrotate(I, st.MinFeretAngle);

Any other ideas how to solve it also as a general solution for object (text, geometric shape, etc)?

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Rotate an object based on regionprops Orientation, MinFeret and MaxFeret angles

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