problem with columnWidth..how solve it
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size(T)
ans =
73 9
T =
73×9 table
T.ColumnWidth={50,30,30,30,30,30,30,30,30}
Error using .
To assign to or create a variable in a table, the number of rows must match the height of the table.
12 个评论
Dyuman Joshi
2023-10-22
移动：Dyuman Joshi
2023-10-22
The size of the data to be added to the table must be compatible with the dimensions of the table, which is what the error message (explicitly) states as well.
Use -
T.ColumnWidth = [50;30;30;30;30;30;30;30;30];
aldo
2023-10-22
移动：Dyuman Joshi
2023-10-22
aldo
2023-10-22
移动：Dyuman Joshi
2023-10-22
Dyuman Joshi
2023-10-22
移动：Dyuman Joshi
2023-10-22
Can you attach the variable T?
aldo
2023-10-22
移动：Dyuman Joshi
2023-10-22
Dyuman Joshi
2023-10-22
编辑：Dyuman Joshi
2023-10-22
I somehow mixed up the dimensions, Sorry.
The table has 73 rows, thus the data for ColumnWidth should have 73 rows as well.
Do you want to add the data related to a variable present in the column? Or is there a criteria/logic for adding that data?
If you have a uitable (UIT) whose data is a table variable (T)
UIT = uitable(); % create a uitable (graphics object)
UIT.Data = T; % set the uitable's Data to be the table variable T
Then you can set the ColumnWidth of the uitable like this:
UIT.ColumnWidth = {50,30,30,30,30,30,30,30,30}; % UIT has 9 columns
However, using the same syntax on the table variable T tries to add a variable/column called "ColumnWidth" to the table T, which produces an error in this case because the number of values given doesn't match the number of rows of T.
T.ColumnWidth = {50,30,30,30,30,30,30,30,30} % T has 73 rows, so this doesn't work
aldo
2023-10-22
Dyuman Joshi
2023-10-22
And what does width mean here?
aldo
2023-10-22
aldo
2023-10-23
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