if difference between two values is smaller than replace by

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Kai
Kai 2023-10-22
评论： Dyuman Joshi 2023-10-23
I have a vector that contains several time values. For the application I need to check if the difference between two values is smaller than 3e-6. If that's the case the second (higher) value shall be replaced with the first.
My approach would be for-loops but maybe there is a smarter and more efficient way to solve this?
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the cyclist
the cyclist 2023-10-22
Ran in:
Is each column processed independently?
As @Dyuman Joshi asked, do you only need to check consecutives values?
It doesn't seem that any value is greater than the immediately preceding value by less than 3.e-6, but more than zero:
load("time.mat","time")
any((diff(time) > 0) & (diff(time) < 3.e-6),"all")
ans = logical
0
Walter Roberson
Walter Roberson 2023-10-22
编辑：Walter Roberson 2023-10-22
Ran in:
load("time.mat","time")
dt = diff(time);
dt = dt(dt ~= 0);
min(dt)
ans = 1.3500e-05
So in all cases where the difference in times is < 3e-6, the two values are already identical.

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Pratyush
Pratyush 2023-10-23
Hi Kai,
I understand that you have a vector, and if the difference between any two values is less than 3e-6, you want to set them both equal to the lesser of the two numbers. The following script could be used for that purpose:
% Sort timeValues vector
timeValues = sort(timeValues);
% Calculate the differences between adjacent values
diffValues = diff(timeValues);
% Find the indices where the differences are smaller than 3e-6
replaceIndices = find(diffValues < 3e-6);
% Replace the second value with the first for the identified indices
timeValues(replaceIndices + 1) = timeValues(replaceIndices);
Hope this helps.
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Dyuman Joshi
Dyuman Joshi 2023-10-23
Note that this answer sorts the data before finding difference between consecutive elements.
OP has/had not specified anything in regards to that.

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