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Unable to perform assignment because the indices on the left side are not compatible with the size of the right side

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Louis du Pisani
Louis du Pisani 2023-10-22
评论： Walter Roberson 2023-10-23
I have a window frame B and B is an array of 1x(length(frame)). I have a signal that is divided into 10 segments that is as long as length(frame) with 50% overlap 'hop' that is hop = length(frame)/2. The segment is saved in an array 'Fil' of size length(frame) x 19. I want to take the fft of every segment with a window applied to it.It is all done in a for loop with k = 20 and FFT is a newly created array in the loop. I used this line of code but it give me the error in the title.
for n = 1:k -1
FFT(:,n) = fft(B'.*Fil(:,n));
end

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Walter Roberson
Walter Roberson 2023-10-22
Give the command window command
dbstop if error
Run the code. When it stops, query
n
size(B.')
size(Fil(:,n))
size(fft(B'.*Fil(:,n)))
whos FFT
and tell us the results
  2 个评论
Louis du Pisani
Louis du Pisani 2023-10-23
Thank you.
FFT still had the dimensions of the previous execution of the code and that is why the indices did not match for the new signal.
I want to post my results, but I had to use 'assignin' to get the variable into my workspace since I am coding in Matlab App Designer.
Walter Roberson
Walter Roberson 2023-10-23
You should be using functions... then you would not have to worry about the possibility of left-over arrays of incompatible size in local variables.

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