??? Error using ==> eq Matrix dimensions must agree

2015 4 15
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更新时间：2015 4 15
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[row, column]=find(My_matrix== pnode); I try to use this command and i get this error
??? Error using ==> eq Matrix dimensions must agree
What should i do?How i should write the syntaxis of it?

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Adam
Adam 2015-4-15
What are the dimensions of My_matrix and pnode? I assume they are not the same size since you get that error and in that case it is impossible for any of us to know what your intention is in trying to test equality between them just from the information you have given.
Giannakis Stoukas
Giannakis Stoukas 2015-4-15
pnode is a variable and it has a value and the matrix has dimensions 10X14,this is why it is weird
Giannakis Stoukas
Giannakis Stoukas 2015-4-15
Actually the previous orders are min_cost = min(x(:)); [pnode, node] = find(x == min_cost); [row, column]=find(My_matrix == pnode); [rows, columns]=find(My_matrix==node);
and the min_cost instead of taking one value it takes an array

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回答（1 个）

John D'Errico
John D'Errico 2015-4-15
编辑：John D'Errico 2015-4-15

0 个投票

Your matrices are not compatible in size. READ THE ERROR MESSAGE!
Try this:
whos MY_matrix pnode
What does it tell you?

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Giannakis Stoukas
Giannakis Stoukas 2015-4-15
The weird is that pnode is a variable with a single value,it isnt a matrix nor an array
Giannakis Stoukas
Giannakis Stoukas 2015-4-15
编辑：John D'Errico 2015-4-15
Actually the previous orders are
min_cost = min(x(:));
[pnode, node] = find(x == min_cost);
[row, column]=find(My_matrix == pnode);
[rows, columns]=find(My_matrix==node);
and the min_cost instead of taking one value it takes an array
John D'Errico
John D'Errico 2015-4-15
I see that the last line has
find(My_matrix==node);
Even if pnode is a scalar, node may well not be so, since it was created from a previous call to find.

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