How to plot this function with 2 variables?
显示 更早的评论
Hello, I’m having a hard time plotting z2(t). I keep getting the error “input must be a function or functions of a single variable”. I’m not sure how to properly define “u”.
2 个评论
Marisa
2023-10-30
Dyuman Joshi
2023-10-30
移动：Dyuman Joshi
2023-10-30
And the syntax to define a function handle is
name_of_handle = @(independent_variables) relation_or_expression_of_independent_variables
%For the first example, it translates to
z1 = @(t) exp(t);
Refer to these links for more information -
回答（1 个）
t = -2:0.01:2;
z1 = exp(t);
z2 = 2*(t+1 >= 0);
z3 = 0.5*sin(7*t);
hold on
grid on
plot(t,z1,'-','LineWidth',2)
plot(t,z2,':','LineWidth',2)
plot(t,z3,'--','LineWidth',2)
xlabel('t')
ylabel('z')
legend("z"+[1 2 3])
ylim([-1 8])
9 个评论
Dyuman Joshi
2023-10-30
Just a note -
z2 = 2*(t+1 >= 0);
">= 0" is not mentioned in the question
Voss
2023-10-30
I interpret u(t) to be the unit step function.
Dyuman Joshi
2023-10-30
Alright.
Marisa
2023-10-30
The signal u(·) in the question most likely refers to the unit step function, which can be represented by the Heaviside function.
t = -2:0.001:2;
z2 = 2*heaviside(t + 1);
plot(t,z2,':','LineWidth',2), grid on
xlabel('t')
ylabel('z')
ylim([-1 8])
Marisa
2023-10-30
Sam Chak
2023-10-30
Hi @Marisa
In the mathematical representation of linear physical systems (later in your course), you may encounter the state-space equation, 
. But this 
is not the unit step function. Please keep that in mind.
. But this is not the unit step function. Please keep that in mind.类别
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2023-10-30
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