Fisher's z transform with atanh() to rho goes to infinity

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Alba Peris 2023-10-31

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https://ww2.mathworks.cn/matlabcentral/answers/2041066-fisher-s-z-transform-with-atanh-to-rho-goes-to-infinity

编辑： MByk 2024-5-13

采纳的回答： Sam Chak

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I have run Spearman's correlations usign the following:

[rho, pval] = corr(A,B, 'type', 'Spearman', 'rows', 'complete');

I would like to conduct a fisher's z transform on my rho values so that I can compare them later on.

Doing

atanh(rho)

sometimes outputs Inf or -Inf (particularly when the output of rho is 1 / -1). In cases where the output of rho is 1.000 or -1.000 this doesn't occur.

I'm not entirely sure what I have missed or how I could fix this issue. Any help will be very much appreciated.

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采纳的回答

Sam Chak 2023-10-31

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https://ww2.mathworks.cn/matlabcentral/answers/2041066-fisher-s-z-transform-with-atanh-to-rho-goes-to-infinity#answer_1344366

移动：Sam Chak 2023-10-31

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Hi @Alba Peris, If you make sure that rho stays in the range

, then

will be finite.

rho = -0.999:0.001:0.999;

y = atanh(rho);

plot(rho, y), grid on, xlabel('\rho'), ylabel('y')

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Sam Chak 2024-5-13

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@MByk, Try this:

idx       = find(abs(yOut - 1) < eps)  % find the position
yOut(idx) = 0.9999

MByk 2024-5-13

Thank you very much.

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