eci2lla altitude error?
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In the following example,
lla = eci2lla([-6.07 -1.28 0.66]*1e6,[2010 1 17 10 20 36])
How do you end up with a negative altitude?
The altitude should be approximately 312000 m.
4 个评论
Dyuman Joshi
2023-11-7
Though it is not specified in the documentation of eci2lla about this, but I presume that the altitude is measured from sea-level.
Going under it would give a negative value.
Derrick Early
2023-11-7
Dyuman Joshi
2023-11-7
"The example should yield a positive altitude."
Why? Did you calculate the values by hand and compare?
Derrick Early
2023-11-7
采纳的回答
lla = eci2lla([-6.07 -1.28 0.66]*1e6,[2010 1 17 10 20 36]);
lat = lla(1)
lon = lla(2)
So, this point is slightly above the Equator (by about 6 degrees)
dist = vecnorm([-6.07 -1.28 0.66]*1e6) % distance of this point from the center of the Earth
equatorialRadius = 6378e3;
dist - equatorialRadius
alt = lla(3)
So this point is beneath the surface of the Earth by about 140 kilometers (negative altitude).
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