Using repelem to vertially concatonate non-numeric variable

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Emu
Emu 2023-11-9
移动：Stephen23 2024-9-23
I have a variable in format 1001_1_1 that changes in a loop. I want to replicate and vertcat this by different amounts each loop, to a new variable eg
1001_1_1
1001_1_1
3005_3_5
3005_3_5
3005_3_5
and so on.
Ive tried using repelem:
new_var = repelem(name, n)
new_var_all = [new_var_all; new_var];
but if e.g. n=3, this is the result: 111000000666___111___333
Please help!

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采纳的回答

Star Strider
Star Strider 2023-11-9
Ran in:
I am not certain what you want to do, however the repmat function might be a better choice, since it allows the dimensions to be specified.
v = '1001_1_1';
new_var = repmat(v, 3, 1)
new_var = 3×8 char array
'1001_1_1' '1001_1_1' '1001_1_1'
.
  1 个评论
Atsushi Ueno
Atsushi Ueno 2023-11-9
Ran in:
n = 3;
new_var_all = [];
name = {'1001_1_1';'3005_3_5';'6007_7_9'};
for k = 1:size(name)
new_var = repmat(name{k}, n, 1);
new_var_all = [new_var_all; new_var];
end
new_var_all
new_var_all = 9×8 char array
'1001_1_1' '1001_1_1' '1001_1_1' '3005_3_5' '3005_3_5' '3005_3_5' '6007_7_9' '6007_7_9' '6007_7_9'

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更多回答（2 个）

Stephen23
Stephen23 2023-11-9
编辑：Stephen23 2023-11-9
Ran in:
".. repmat function might be a better choice, since it allows the dimensions to be specified."
As does REPELEM:
repelem('1001_1_1',3,1)
ans = 3×8 char array
'1001_1_1' '1001_1_1' '1001_1_1'
Steven Lord
Steven Lord 2023-11-9
Ran in:
Note that the for loop approach from @Atsushi Ueno works if the "pieces" of the names are the same length all the way down the list. But if you had:
name = {'1001_1_1';'3005_3_5';'6007_7_10'}; % 10 not 9
you'd receive an error. In this case, I'd use a string array and repmat or repelem as @Star Strider and @Stephen23 suggested.
names = ["1001_1_1";"3005_3_5";"6007_7_10"];
R = repelem(names, 3, 1)
R = 9×1 string array
"1001_1_1" "1001_1_1" "1001_1_1" "3005_3_5" "3005_3_5" "3005_3_5" "6007_7_10" "6007_7_10" "6007_7_10"
If you need the elements as char vectors (because a function you're trying to use only supports char vectors or would need to be modified to support string arrays, like if it uses concatenation to combine the name with something else) you can call char.
c = char(R(8))
c = '6007_7_10'
Another possibility, if you're trying to assemble these names from all combinations of the "pieces", is to use combinations and join.
C = combinations([1001, 3005, 6007], [1, 3, 7], [1, 5, 10]);
join(string(C.Variables), "_")
ans = 27×1 string array
"1001_1_1" "1001_1_5" "1001_1_10" "1001_3_1" "1001_3_5" "1001_3_10" "1001_7_1" "1001_7_5" "1001_7_10" "3005_1_1" "3005_1_5" "3005_1_10" "3005_3_1" "3005_3_5" "3005_3_10" "3005_7_1" "3005_7_5" "3005_7_10" "6007_1_1" "6007_1_5" "6007_1_10" "6007_3_1" "6007_3_5" "6007_3_10" "6007_7_1" "6007_7_5" "6007_7_10"

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