Function won't index properly

13 次查看（过去 30 天）
Ammar
Ammar 2011-11-6
I have created the following function to find the index numbers of the elements of array a that are less than or equal to b, whether be is a scalar or another array of length(a)=length(b).
function [m,k]=my_find(a,b)
for i=1:length(a)
if length(b)==1
k(i)=(a(i)<=b);
if k==1
m=i;
end
elseif length(b)==length(a)
k(i)=(a(i)<=b(i));
if k==1
m=i;
end
else
disp('Error')
end
end
disp('m = '),disp(m)
disp('k = '),disp(k)
For some reason, the m value does not index properly, even though the k value returns the proper values. The m value if supposed to replace the use of the find function. Any suggestions?

请先登录，再回答此问题。

采纳的回答

Andrei Bobrov
Andrei Bobrov 2011-11-6
function [m, k] = Ammar_find(a,b)
na = numel(a);
nb = numel(b);
if nb ~= na && nb > 1,
disp('size "a" and "b" are not consistent');
m = [];
k = [];
else
k = a <= b;
m = nonzeros(k.*reshape(1:na,size(a)));
end
variant
function [m, k] = Ammar_find(a,b)
try
k = a <= b;
m = nonzeros(k.*reshape(1:na,size(a)));
catch err
rethrow(err);
end
  1 个评论
Ammar
Ammar 2011-11-8
Brilliant. The first method worked perfectly. (I never tried the second one.) Never would have come up with this on my own.

请先登录，再进行评论。

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Matrices and Arrays 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by