piecewise function and function handles

Hi everybody, I have a little trouble issues with my function handles.
In particular I am trying to describe a function handle which has a specific value (related to two variables) in a range of one of the two vairables, and 0 otherwise.
E_2rad=0.79;
@(freq_wave,wave_angle) (0<= wave_angle <= pi-E_2rad) .* ((2.25/4)*ro_w*g*B*0.75).*(sin(E_2rad+wave_angle).^2+(2.*freq_wave.*(vel_nave/g).*(cos(E_2rad).*cos(E_2rad+wave_angle)...
-cos(wave_angle)))) + (wave_angle > pi-E_2rad) .* 0
the function written as above mentioned returns a value different from 0 if wave_angle > pi-E_2rad instead and I cannot understand why and how to fix it. Thanks in advance for your help

 采纳的回答

You need to define multiple conditions separately/individually i.e -
This
(0<= wave_angle <= pi-E_2rad)
should be -
(wave_angle >=0) && (wave_angle <= pi-E_2rad)

4 个评论

Hi Dyuman: thanks again for your support.
in this case, I decided to avoid your solution because, after the definition of this function handle i need to sum it with other function handles and integrate them. In fact, after calling a double integration and after separating the multiple conditions, this message appears:
Operands to the || and && operators must be convertible to logical scalar values.
any other suggestion to solve this other trouble?
A silly mistake from my side - It should be a single ampersand i.e. & .
If there is still an error after making the aforementioned change, please share your code and state the error you get.
Don't worry. You couldn't have known about integrals.
By the way all the problems aforementioned are fixed. Thanks again!
The anonymous function is vectorized and so, for the given comparison, I should have noted that it should be a single ampersand. (I really should be going to sleep earlier :P)
Nonetheless, glad to know that your issue is solved. Happy to have helped!

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