piecewise function and function handles

9 次查看（过去 30 天）

Gianluca Angelini 2023-11-21

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/2050297-piecewise-function-and-function-handles

编辑： Dyuman Joshi 2023-11-21

Hi everybody, I have a little trouble issues with my function handles.

In particular I am trying to describe a function handle which has a specific value (related to two variables) in a range of one of the two vairables, and 0 otherwise.

E_2rad=0.79;

@(freq_wave,wave_angle) (0<= wave_angle <= pi-E_2rad) .* ((2.25/4)*ro_w*g*B*0.75).*(sin(E_2rad+wave_angle).^2+(2.*freq_wave.*(vel_nave/g).*(cos(E_2rad).*cos(E_2rad+wave_angle)...

-cos(wave_angle)))) + (wave_angle > pi-E_2rad) .* 0

the function written as above mentioned returns a value different from 0 if wave_angle > pi-E_2rad instead and I cannot understand why and how to fix it. Thanks in advance for your help

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

请先登录，再进行评论。

请先登录，再回答此问题。

采纳的回答

Dyuman Joshi 2023-11-21

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/2050297-piecewise-function-and-function-handles#answer_1357342

在 MATLAB Online 中打开

You need to define multiple conditions separately/individually i.e -

This

(0<= wave_angle <= pi-E_2rad)

should be -

(wave_angle >=0) && (wave_angle <= pi-E_2rad)

4 个评论
显示 2更早的评论隐藏 2更早的评论

Gianluca Angelini 2023-11-21

Don't worry. You couldn't have known about integrals.

By the way all the problems aforementioned are fixed. Thanks again!

Dyuman Joshi 2023-11-21

编辑：Dyuman Joshi 2023-11-21

The anonymous function is vectorized and so, for the given comparison, I should have noted that it should be a single ampersand. (I really should be going to sleep earlier :P)

Nonetheless, glad to know that your issue is solved. Happy to have helped!

请先登录，再进行评论。