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what this equation means 4*L/(2*i-1)?

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BA
BA 2023-11-22
评论： Alexander 2023-11-22
I am trying to convert this equation 4*L/(2*i-1) into R
I failed to undersatnd why the output is two negative values in matlab
but R'output is a single value
L= 17;
i=4;
(2*i-1) gives -1 + 2; Is it i here is a complex number?
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Torsten
Torsten 2023-11-22
编辑：Torsten 2023-11-22
Ran in:
If you use the expression 4*L/(2*i-1) in R, I guess that "i" was set to a value somewhere before in the R-code. If you set "i" to the same value in your MATLB code, MATLAB will compute the same value for the expression as R does. If you don't set "i" to a value before you compute the expression, MATLAB will interprete "i" as the imaginary unit.
L = 17;
i = 4;
4*L/(2*i-1)
ans = 9.7143
clear i
4*L/(2*i-1)
ans = -13.6000 -27.2000i
Alexander
Alexander 2023-11-22
Never use i or j if you are not dealing with complex numbers. Use ii or jj instead if you have to.

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采纳的回答

ScottB
ScottB 2023-11-22
Yes, Matlab sees "i" as complex. Maybe pick another variable if you are just using scalars.

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