How can I rotate the axes' labels parallel to the orientation of the axes?

Question

Navid 2023-11-23

4
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/2051492-how-can-i-rotate-the-axes-labels-parallel-to-the-orientation-of-the-axes

评论： Navid 2023-11-28

Hi. I would like to know how to rotate labels and keep them centered with their orientation. Please see Fig 1. This figure is the default view output using the following syntax.

xlabel('x','Rotation',35)

ylabel('y','Rotation',-35)

However, in Fig 2, the plot view is set to:

view([73 24])

Is there a solution to rotate the labels parallel to the orientation of the axes by changing the view values? In this case, the 'Rotation' value (in this example, 35 and -35) changes as a function of the 'View' value (i.e., 73 and 24). Thank you so much for your time and consideration.

[X,Y,Z] = peaks(25);

figure

subplot(1,2,1)

surf(X,Y,Z);

xlabel('x','Rotation',35)

ylabel('y','Rotation',-35)

zlabel('z')

title('Fig.1')

subplot(1,2,2)

surf(X,Y,Z);

xlabel('x')

ylabel('y')

zlabel('z')

view([73 24])

title('Fig.2')

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Answer 1

Bruno Luong 2023-11-24

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/2051492-how-can-i-rotate-the-axes-labels-parallel-to-the-orientation-of-the-axes#answer_1359022

编辑：Bruno Luong 2023-11-24

在 MATLAB Online 中打开

Try this (the letters of label are rotated but the aspect ratio remain constant so they can be read easily but are not look like "projected" on the xy plane)

The angles depend on figure/axes aspect ratio, so if you resize them you have to compute the angle again.

[X,Y,Z] = peaks(25);

fig = figure(1);

clf(fig);

t = tiledlayout(2,2);

for k = 1:prod(t.GridSize)

ax = nexttile(t);

surf(ax, X, Y, Z);

%axis(ax, 'equal')

view(ax, rand*360, 40); % random azimuth

set(ax,'unit','pixel');

axPosition = ax.Position;

dx = axPosition(3);

dy = axPosition(4);

[xx, xy] = ScreenProjection(ax, xlim(ax), [0 0], [0 0]);

thetax = atan(diff(xy)/diff(xx)*dy/dx);

xlabel('here is the x-label', 'Rotation', rad2deg(thetax))

[xx, xy] = ScreenProjection(ax, [0 0], ylim(ax), [0 0]);

thetay = atan(diff(xy)/diff(xx)*dy/dx);

ylabel('here is the y-label', 'Rotation', rad2deg(thetay))

zlabel('z')

end

% https://www.mathworks.com/matlabcentral/answers/430790-how-can-i-get-the-screen-coordinates-from-perspective-projection?s_tid=srchtitle

function [xcam, ycam] = ScreenProjection(ax, X, Y, Z)

dataRatio = get(ax, 'DataAspectRatio');

matrixRescale = diag(1./dataRatio);

CT = get(ax,'CameraTarget');

CP = get(ax,'CameraPosition');

CU = get(ax,'CameraUpVector');

cadeg = get(ax,'CameraViewAngle');

CT = CT(:);

CP = CP(:);

CU = CU(:);

ca = cadeg*pi/180;

%

c = CT-CP;

d = norm(c);

c = c / d;

u = CU - dot(c, CU)*c;

u = u/norm(u);

p = cross(c,u);

R=[c,p,u];

XYZ = [X(:),Y(:),Z(:)]';

CPU = R'*(matrixRescale*(XYZ-CP));

XYcam = CPU(2:3,:)./CPU(1,:);

xcam = XYcam(1,:);

ycam = XYcam(2,:);

end

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Bruno Luong 2023-11-24

编辑：Bruno Luong 2023-11-24

在 MATLAB Online 中打开

tiltelayout It is not important to compute the angle of labels, replace nextile with subplot command

[X,Y,Z] = peaks(25);

fig = figure(1);

clf(fig);

for k = 1:4

ax = subplot(2,2,k);

surf(ax, X, Y, Z);

%axis(ax, 'equal')

view(ax, rand*360, 40); % random azimuth

set(ax,'unit','pixel');

axPosition = ax.Position;

dx = axPosition(3);

dy = axPosition(4);

[xx, xy] = ScreenProjection(ax, xlim(ax), [0 0], [0 0]);

thetax = atan(diff(xy)/diff(xx)*dy/dx);

xlabel('here is the x-label', 'Rotation', rad2deg(thetax))

[xx, xy] = ScreenProjection(ax, [0 0], ylim(ax), [0 0]);

thetay = atan(diff(xy)/diff(xx)*dy/dx);

ylabel('here is the y-label', 'Rotation', rad2deg(thetay))

zlabel('z')

end

% https://www.mathworks.com/matlabcentral/answers/430790-how-can-i-get-the-screen-coordinates-from-perspective-projection?s_tid=srchtitle

function [xcam, ycam] = ScreenProjection(ax, X, Y, Z)

dataRatio = get(ax, 'DataAspectRatio');

matrixRescale = diag(1./dataRatio);

CT = get(ax,'CameraTarget');

CP = get(ax,'CameraPosition');

CU = get(ax,'CameraUpVector');

cadeg = get(ax,'CameraViewAngle');

CT = CT(:);

CP = CP(:);

CU = CU(:);

ca = cadeg*pi/180;

%

c = CT-CP;

d = norm(c);

c = c / d;

u = CU - dot(c, CU)*c;

u = u/norm(u);

p = cross(c,u);

R=[c,p,u];

XYZ = [X(:),Y(:),Z(:)]';

CPU = R'*(matrixRescale*(XYZ-CP));

XYcam = CPU(2:3,:)./CPU(1,:);

xcam = XYcam(1,:);

ycam = XYcam(2,:);

end

Bruno Luong 2023-11-28

Disapointly the authority's answer of this thread explains the reason of the flaw and unable to suggest a satisfactition way to center label to axe position, beside "do it manually".

When I have time I'll make a code to position and center the labels.

Navid 2023-11-28