how to plot different horizontal lines over each group of bar plot

4 次查看(过去 30 天)

采纳的回答

Star Strider
Star Strider 2023-12-8
编辑:Star Strider 2023-12-8
Try something like this —
A = (5+rand(10))/6;
figure
hb = bar(A);
for k = 1:numel(hb)
xep(k,:) = hb(k).XEndPoints;
end
L = min(xep);
R = max(xep);
hold on
plot([L(:) R(:)], [1 1]*0.75, '-k', 'LineWidth',3)
hold off
figure
hb = bar(A);
for k = 1:numel(hb)
xep(k,:) = hb(k).XEndPoints;
end
L = min(xep);
R = max(xep);
hold on
plot([L(:) R(:)], [1 1]*0.75, '-k', 'LineWidth',3)
hold off
xlim([0.5 2.5])
Make appropriate changes to get the result you want.
EDIT — (8 Dec 2023 at 13:43)
To extend the lines to cover all the bars in each group (rather than stopping at the midpoints), use the normalised ‘Barwidth’ data as well to extend it —
A = (5+rand(10))/6;
figure
hb = bar(A);
BW = hb.BarWidth
BW = 0.8000
for k = 1:numel(hb)
xep(k,:) = hb(k).XEndPoints;
end
L = min(xep);
R = max(xep);
hold on
plot([L(:) R(:)]+[-0.5 0.5]*BW/numel(hb), [1 1]*0.75, '-k', 'LineWidth',3)
hold off
figure
hb = bar(A);
BW = hb.BarWidth;
for k = 1:numel(hb)
xep(k,:) = hb(k).XEndPoints;
end
L = min(xep);
R = max(xep);
hold on
plot([L(:) R(:)]+[-0.5 0.5]*BW/numel(hb), [1 1]*0.75, '-k', 'LineWidth',3)
hold off
xlim([0.5 2.5])
.

更多回答(1 个)

Dyuman Joshi
Dyuman Joshi 2023-12-8
Here's a demo -
%Random data
mat = randi([11 19], 4, 6);
%Bar plot
b = bar(mat);
hold on
%Get the x-coordinates of each group (center of each bar)
%Each column represents the x-coordinates of each bar group
x = vertcat(b.XEndPoints)
x = 6×4
0.6667 1.6667 2.6667 3.6667 0.8000 1.8000 2.8000 3.8000 0.9333 1.9333 2.9333 3.9333 1.0667 2.0667 3.0667 4.0667 1.2000 2.2000 3.2000 4.2000 1.3333 2.3333 3.3333 4.3333
%Get the coordinates of the end points
x = x([1 end],:).'
x = 4×2
0.6667 1.3333 1.6667 2.3333 2.6667 3.3333 3.6667 4.3333
plot(x, [5 5], 'LineWidth', 2.5, 'Color', 'k');
hold off

类别

Help CenterFile Exchange 中查找有关 Annotations 的更多信息

标签

产品


版本

R2022a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by