Split array into groups of close numbers

a = [1,2,3,10,11];
n = 2;
x = kmeans(a(:),n)
x = 5×1
     2
     2
     2
     1
     1
c = accumarray(x,a(:),[],@(a){a})
c = 2×1 cell array
    {2×1 double}
    {3×1 double}

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Answer 2

Walter Roberson 2023-12-8

0
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No -- because there is no rigourous meaning to what "close" means.

For example, in [1 3 5 7], surely 1 is not "close" to 7, but 5 is (probably) close to 7. Then 3 is "close" to 5, and 1 is "close" to 3. So are they all to be considered close as a group, even though 1 is "far" from 7 ?

Now, if the question were about dividing up into groups of consecutive values, then that would not be too difficult.

You could also use something like

N = 2;
a = [1 2 3 10 11]
a = 1×5
     1     2     3    10    11
[g, centroids] = kmeans(a(:), N)
g = 5×1
     1
     1
     1
     2
     2
centroids = 2×1
    2.0000
   10.5000