Fixing Incompatible Sizes while Calculating Absolute Vorticity

Question

Jonathon Klepatzki 2023-12-11

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https://ww2.mathworks.cn/matlabcentral/answers/2059309-fixing-incompatible-sizes-while-calculating-absolute-vorticity

回答： Nipun 2023-12-26

I want to calculate the relative and absolute voriticity change using the following specifications. Then make a video out of it as it changes in height. However, I get errors with incompatible sizes and or dimensions. I do know whether or not the code for the video works...if anyone can help it would be much appreciated.

close all;
clear all;
clc;
curve = animatedline('LineWidth',2)
hold on;
grid on;
title('Temperant Absolute Vorticity Change');
partialu = 150; % in ms^-1
partialv = 120; % in ms^-1
partialx = (5:2100); %in meters
partialy = (9:4200); %in meters
T1 = (27:32);
T2 = (24:21);
dT = T2-T1;
dz = (30:168); % change in height
lapserate = dT./dz;
omega = 7.29*10^-5;
phi = 35; % change in latitude
dt = 0:60; % change in time in seconds
planetaryvort = 2*omega*sin(phi);
for i = 1:length(partialx)
    for j = 1:length(partialy)
        for t = 1:length(dt)
            relativevort = partialv./partialx - partialu./partialy;
            absolutvore = lapserate*(relativevort+planetaryvort)./dt;
            
            F(i) = getframe(gca);
            pause(0.01);
            delete(head);
        end
    end
end
video = VideoWriter('Temperant Absolute Vorticity Change','Uncompressed AVI');
open(video)
writeVideo(video,F)

7 个评论
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Jonathon Klepatzki 2023-12-12

Sadly no. After I clicked run, it would not bring up the video. I think maybe perhaps the size maybe the problem with it.

Avni Agrawal 2023-12-21

Hi Jonathon, can you share the updated code after the error fixes?

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Answer 1

Nipun 2023-12-26

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https://ww2.mathworks.cn/matlabcentral/answers/2059309-fixing-incompatible-sizes-while-calculating-absolute-vorticity#answer_1377787

在 MATLAB Online 中打开

Hi Jonathon,

I understand that you are trying to calculate the relative and absolute vorticity change using the specifications as dictated by your code, but you are getting a "dimension incompatible" error.

On analyzing your code, I have found that "dT" can not be evaluated since "T1" and "T2" have different sizes.

T2 = 24:21
% T2 has size 1,0 since the end point is smaller than starting point
% to get a series 24 23 22 21, do:
T2 = 24:-1:21

However, the error will still persist since "T1" has size "1 x 6" and "T2" (after correction) has size "1 x 4"

MATLAB does not support subtraction in vectors of different lengths.

I recommend either fixing your declaration of "T1" and "T2" to make sure they have the same dimensions. Or you, may consider padding "T2" with zeros ro support the subtraction operation.

Hope this helps.

Regards,

Nipun