How do I break an array into individual element without using loops

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Olayinka 2023-12-16

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/2061302-how-do-i-break-an-array-into-individual-element-without-using-loops

评论： Olayinka 2023-12-20

x=[3,4,5,6,7,8,9,10]
x = 1×8
     3     4     5     6     7     8     9    10
for i=1:length(x)
    y=x(i)
end
y = 3
y = 4
y = 5
y = 6
y = 7
y = 8
y = 9
y = 10

I want a function to give me this result without using a loop

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DGM 2023-12-17

编辑：DGM 2023-12-17

Repetition doesn't answer the question. The example you gave is ostensibly the thing you want, but in that example, y is a scalar which changes value with each loop iteration. So if there is no loop, what is the equivalent? I posed two interpretations:

A single scalar variable which is multivalued (which is nonsense)
A pile of numbered scalar variables (which are not practically addressable)

If we assume that you mean to create a pile of numbered variables, then there's another question you need to answer. Once you have a hundred numbered variables in memory, how do you intend on addressing them? Spoiler: the solution to the unnecessary problem you're creating is another problem.

As to how you'd create them all those variables, well that would still involve a loop. If you don't want a loop, then you're going to have to write it all out like @Image Analyst pointed out. At that point, if you just intend on writing out every single operation on every single element of every array in your entire workflow, then what's the point in using MATLAB to do it?

Olayinka 2023-12-20