Accessing all fields within a struct level at once
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If I have a struct A which looks like:
A.('one').('include') ; A.('two').('include'); A.('three').('dont include');
and so on, how can I directly check if 'dont include' is present in the third level of the structure without having to use a loop. Is this possible to achieve without implementing a loop?
采纳的回答
"Is this possible to achieve without implementing a loop?"
Not really, but you can hide the loop using STRUCTFUN:
A.one.include = 1;
A.two.include = 2;
A.three.dontinclude = 3;
F = @(s)isfield(s,'dontinclude');
structfun(F,A)
更多回答（1 个）
Hi Vaishnavi,
I understand that you are trying to find if "dontinclude" is a structure property without using for loops.
One possible solution is to create a function which evaluates every level of structure to check if the property is present.
Here is an example code with the listed recommendation
funcCheck = @(struct)isfield(struct,'dontinclude');
structfun(funcCheck,A)
Returns a "n x 1" logical array, where "n" is the number of levels in the structure.
Link to documentation:
Hope this helps.
Regards,
Nipun
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