Convert matlab index vector to 2D array based on gaps

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Hi all,
I am asking to get feedback on my code and see if there are other ways to programme this basic algorithm more efficiently or elegantly.
out = segments([1 end]); % Start point of first interval
for idx = find(diff(segments) > 1) % Iterate over gaps
out(end, 2) = segments(idx); % End point of current interval
out(end + 1, 1) = segments(idx + 1); % Start point of next interval
end
out(end, 2) = segments(end); % End point of last interval
out(:, diff(out, [], 2) == 0) = []; % Remove point intervals
E.g., for segments = [12 13 14 16 17 18], the output out = [12 14; 16 18] noting the gap between 14 and 16.

采纳的回答

Dyuman Joshi
Dyuman Joshi 2023-12-21
You can vectorize the code -
seg = [12 13 14 16 17 18 20 21 22 23 24];
idx = diff(seg)~=1;
out = [seg(1) seg([false idx]); seg([idx false]) seg(end)].'
out = 3×2
12 14 16 18 20 24
  4 个评论
Dyuman Joshi
Dyuman Joshi 2023-12-24
编辑:Dyuman Joshi 2023-12-24
Updated code -
seg = [12 13 14 16 17 18 20 21 22 23 24];
idx = diff(seg)~=1;
out = [seg([true idx]); seg([idx true])].'
out = 3×2
12 14 16 18 20 24
Stephen23
Stephen23 2023-12-24
编辑:Stephen23 2023-12-24
"Is there a reason why the transpose is written as .' instead of just '?"
Because .' is transpose (even if beginners often use the complex conjugate transpose instead):
Using the correct operator has several benefits:
  • it makes the intent clear
  • it makes your code more generalized (assuming the rest of your algorithm can also handle complex numbers)
  • it increases trust in your code
  • it is the correct operator

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