Convert matlab index vector to 2D array based on gaps
显示 更早的评论
Hi all,
I am asking to get feedback on my code and see if there are other ways to programme this basic algorithm more efficiently or elegantly.
out = segments([1 end]); % Start point of first interval
for idx = find(diff(segments) > 1) % Iterate over gaps
out(end, 2) = segments(idx); % End point of current interval
out(end + 1, 1) = segments(idx + 1); % Start point of next interval
end
out(end, 2) = segments(end); % End point of last interval
out(:, diff(out, [], 2) == 0) = []; % Remove point intervals
E.g., for segments = [12 13 14 16 17 18], the output out = [12 14; 16 18] noting the gap between 14 and 16.
采纳的回答
You can vectorize the code -
seg = [12 13 14 16 17 18 20 21 22 23 24];
idx = diff(seg)~=1;
out = [seg(1) seg([false idx]); seg([idx false]) seg(end)].'
4 个评论
ErikJ GiesenLoo
2023-12-21
Dyuman Joshi
2023-12-21
编辑：Dyuman Joshi
2023-12-21
Yes, that's it!
As for the tranpose, it's a habit. Since we are dealing with real numbers, .' is equal to ' . So you can use either of them here.
Updated code -
seg = [12 13 14 16 17 18 20 21 22 23 24];
idx = diff(seg)~=1;
out = [seg([true idx]); seg([idx true])].'
"Is there a reason why the transpose is written as .' instead of just '?"
Because .' is transpose (even if beginners often use the complex conjugate transpose instead):
Using the correct operator has several benefits:
- it makes the intent clear
- it makes your code more generalized (assuming the rest of your algorithm can also handle complex numbers)
- it increases trust in your code
- it is the correct operator
更多回答（0 个）
类别
在 帮助中心 和 File Exchange 中查找有关 Logical 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Translated by 
