Vectorized generation of a cell

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Amir Mahmoudi
Amir Mahmoudi 2023-12-22
评论： Matt J 2023-12-23
x = 1 : a; y = 1 : b; z(x,y) = {randperm(d,2)}; a non-repeating cell is desired. No for loops please.
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Jon
Jon 2023-12-22
How are the values of a and b used. What is the value of d?

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Matt J
Matt J 2023-12-22
编辑：Matt J 2023-12-22
Ran in:
There is no way to create or manipulate cells without for-loops. Things like mat2cell, num2cell, etc... all have for-loops inside them. So do things like cellfun, arrayfun, etc...
It is not clear why you would want a cell array. Your data can be stored in an a-by-b-by-2 array.
a=5; b=3; d=7;
I=nchoosek(1:d,2);
I=[I;fliplr(I)];
r=randi(height(I),a*b,1);
z= reshape(I(r,:) ,a,b,2)
z =
z(:,:,1) = 5 1 1 2 1 1 3 4 2 5 1 1 1 1 5 z(:,:,2) = 7 5 5 5 3 4 5 7 7 6 7 6 2 3 6
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Amir Mahmoudi
Amir Mahmoudi 2023-12-23
I accepted the answer because of the comments. The answer is not what I wanted.
Matt J
Matt J 2023-12-23
Ran in:
It must be a cell. If there is no way, then I have to use for loops.
If you don't care about avoiding for-loops anymore, you can take the result of my proposed code and convert it to a cell with num2cell:
a=5; b=3; d=7;
I=nchoosek(1:d,2);
I=[I;fliplr(I)];
r=randi(height(I),a*b,1);
z= reshape( num2cell(I(r,:),2) ,a,b)
z = 5×3 cell array
{[6 2]} {[2 1]} {[5 7]} {[4 5]} {[3 5]} {[5 7]} {[1 2]} {[7 3]} {[4 7]} {[7 5]} {[3 7]} {[1 4]} {[1 4]} {[2 4]} {[2 6]}

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