Vectorized generation of a cell

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Amir Mahmoudi 2023-12-22

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https://ww2.mathworks.cn/matlabcentral/answers/2063362-vectorized-generation-of-a-cell

评论： Matt J 2023-12-23

采纳的回答： Matt J

x = 1 : a; y = 1 : b; z(x,y) = {randperm(d,2)}; a non-repeating cell is desired. No for loops please.

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Jon 2023-12-22

How are the values of a and b used. What is the value of d?

Amir Mahmoudi 2023-12-22

a, b, d are any numbers.

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采纳的回答

Matt J 2023-12-22

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https://ww2.mathworks.cn/matlabcentral/answers/2063362-vectorized-generation-of-a-cell#answer_1376482

编辑：Matt J 2023-12-22

在 MATLAB Online 中打开

There is no way to create or manipulate cells without for-loops. Things like mat2cell, num2cell, etc... all have for-loops inside them. So do things like cellfun, arrayfun, etc...

It is not clear why you would want a cell array. Your data can be stored in an a-by-b-by-2 array.

a=5; b=3; d=7;
I=nchoosek(1:d,2);
I=[I;fliplr(I)];
r=randi(height(I),a*b,1);
z= reshape(I(r,:)   ,a,b,2)
z = 
z(:,:,1) =

     5     1     1
     2     1     1
     3     4     2
     5     1     1
     1     1     5


z(:,:,2) =

     7     5     5
     5     3     4
     5     7     7
     6     7     6
     2     3     6

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Amir Mahmoudi 2023-12-23

I accepted the answer because of the comments. The answer is not what I wanted.

Matt J 2023-12-23

在 MATLAB Online 中打开

It must be a cell. If there is no way, then I have to use for loops.

If you don't care about avoiding for-loops anymore, you can take the result of my proposed code and convert it to a cell with num2cell:

a=5; b=3; d=7;
I=nchoosek(1:d,2);
I=[I;fliplr(I)];
r=randi(height(I),a*b,1);
z= reshape(  num2cell(I(r,:),2)   ,a,b)
z = 5×3 cell array
    {[6 2]}    {[2 1]}    {[5 7]}
    {[4 5]}    {[3 5]}    {[5 7]}
    {[1 2]}    {[7 3]}    {[4 7]}
    {[7 5]}    {[3 7]}    {[1 4]}
    {[1 4]}    {[2 4]}    {[2 6]}