Newtons law of cooling
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At time t=0, T=100 which cools down to T=75 in 2 min,then further I need to find T at t=4,5,8.The issue is I am not given cooling constant K and it is not to be assumed 1/min Equation is dT/dt = k*(T-T_0) where T_0 is 30
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Sulaymon Eshkabilov
2023-12-25
编辑:Sulaymon Eshkabilov
2023-12-27
Is this what you want to compute:
% Given intial data:
T0 = 30;
T_initial = 100;
T_target = 75;
time_step = 2;
% How to calculate the constant k:
syms k t
EQN = T_target==((T_initial - T0)) *exp(k*t)+T0;
k = solve(EQN, k)
t=2;
k=subs(k, t);
k=double(k)
% Diff EQN:
dT = @(T) k * (T - T0);
% Solve the Diff EQN @ t = 4, 5, 8:
t_vals = [4, 5, 8];
for i = 1:length(t_vals)
t = t_vals(i);
% Solution T at given time t:
[time, T] = ode45(@(t, T) dT(T), [0 t], T_initial);
fprintf('At t = %d minutes, T = %.2f\n', t, T(end));
end
If you want more detailed calcs with smaller steps
% Solve the Diff EQN @ t = 4, 5, 8:
t_vals = 2:.5:10;
for i = 1:length(t_vals)
t = t_vals(i);
% Solution T at given time t:
[time, T] = ode45(@(t, T) dT(T), [0 t], T_initial);
fprintf('At t = %d minutes, T = %.2f\n', t, T(end));
end
plot(time, T)
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Sam Chak
2023-12-25
Hi @Habiba
I understand that you are grappling with a certain problem. That's why you've outlined the challenge of not knowing the rate of heat loss, denoted as k. More importantly, you haven't explicitly requested us to solve the problem for you, and this is greatly appreciated. It suggests that you have a keen interest in acquiring knowledge and derive satisfaction from the process of learning how to solve problems.
People perceive and grasp mathematical concepts differently. A math teacher views the world of differential equations through a distinct lens, as they stand on the shoulders of Newton, while a student may be positioned at the feet of Newton.
For instance, if you possess the key to solving first-order linear ordinary differential equations, wherein the solution to
is expressed as (according to the Schaum's Outline of Mathematical Handbook of Formulas and Tables)
,
then you can determine the value of k such that .
By now, you probably have noticed that at , . Since and are known, can you solve the algebraic equation and determine k?
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