Discrepancy in signalLabeler AutomatedValue Function with Multi-channel Data??

Question

Yiding Qiu 2023-12-30

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/2065086-discrepancy-in-signallabeler-automatedvalue-function-with-multi-channel-data

回答： Ayush Modi 2024-1-10

I am working with the signalLabeler in MATLAB and attempting to use the AutomatedValue function as described in the template here:

https://au.mathworks.com/help/signal/ug/label-qrs-complexes-and-r-peaks-of-ecg-signals-using-deep-network.html

openExample('signal/LabelQRSComplexesECGSignalsUsingTrainedDeepNetworkExample')

.

However, contrary to the documentation, when I call the custom function within signalLabeler, the input 'x' is passed as a single-dimension vector rather than a multi-channel matrix or cell array. This inconsistency is also reflected in the provided example, where 'x' is used as one-channel data and the for-loop seems redundant. Also, when I select multiple channels in signalLabeler, the 'x' passed to function is still one-channel data. How can I address this to work with multi-channel ECG data as intended by the function's template?

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

请先登录，再进行评论。

请先登录，再回答此问题。

Answer 1

Ayush Modi 2024-1-10

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/2065086-discrepancy-in-signallabeler-automatedvalue-function-with-multi-channel-data#answer_1387196

在 MATLAB Online 中打开

Hi,

The example in the link provided (https://au.mathworks.com/help/signal/ug/label-qrs-complexes-and-r-peaks-of-ecg-signals-using-deep-network.html) is to demonstrate how you can pass a signal variable (Single or Multi-channel). The for-loop is there to handle both of these cases.

Assuming you are trying to pass a multi-channel signal into the parameter “x”, I replicated the steps mentioned in the example and replaced the signal with my own multi-channel signal (4 channels).

Furthermore, I have added the below line of code to check the size of the signal in the “findQRS” custom function to check the number of channels received in "x":

size(x,2)

The output returned for the above code during execution of the code was 4.

I hope this helps you in understanding the example better.