Unable to use a value of type tf as an index. How to fix?

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Rohan Gulur 2024-1-3

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https://ww2.mathworks.cn/matlabcentral/answers/2065871-unable-to-use-a-value-of-type-tf-as-an-index-how-to-fix

评论： Rohan Gulur 2024-1-3

num=[(-number1),(number2)];
            den=[(number3), (number4))];
            sys1 = tf(num, den);
            fb = bandwidth(sys1)
           

Having issues when running this saying that I am unavailable to use value of TF as an index. Any suggestions to fix this?

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Answer 1

Walter Roberson 2024-1-3

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You will find that bandwidth is a variable but that you are trying to use it as a function call.

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Rohan Gulur 2024-1-3

Hi Walter, how else would I use bandwidth then?

Steven Lord 2024-1-3

Rename the variable you've created that's named bandwidth to something else. While that variable exists in the workspace you will be unable to call the bandwidth function.

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Answer 2

Maven Euler 2024-1-3

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Hi @Rohan Gulur

The error message "Unable to use a value of type tf as an index" suggests that there is a syntax error in the code. It seems like there is an extra parenthesis in the den array definition which is causing the problem.

You can try this code:

number1 = ...; % Your value for number1
number2 = ...; % Your value for number2
number3 = ...; % Your value for number3
number4 = ...; % Your value for number4
num = [-number1, number2];
den = [number3, number4];
sys1 = tf(num, den);
fb = bandwidth(sys1);