Swap shape of cell array full of arrays
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Hey,
I have a nxn cell array where each element contains a 1xm array.
How do I turn this into a 1xm cell array where each element contains a nxn array?
So basically from:
{[1 2 3 4 5], [1 2 3 4 5]; [1 2 3 4 5], [1 2 3 4 5]}
to
{[1 1; 1 1], [2 2; 2 2], [3 3; 3 3], [4 4; 4 4], [5 5; 5 5]}
Thanks!
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采纳的回答
Stephen23
2024-1-15
C = {[1,2,3,4,5], [1,2,3,4,5]; [1,2,3,4,5], [1,2,3,4,5]}
F = @(a)reshape(a,1,1,[]);
D = reshape(num2cell(cell2mat(cellfun(F,C,'uni',0)),1:2),size(C{1}))
D{:}
更多回答(1 个)
Hassaan
2024-1-15
编辑:Hassaan
2024-1-15
Approach 1
% Example input: an nxn cell array
n = 2;
m = 4; % changed from 5 to 4 to make it reshapeable to 2x2
inputCellArray = cell(n, n);
for i = 1:n
for j = 1:n
inputCellArray{i, j} = 1:m; % changed from [1 2 3 4 5] to 1:4
end
end
% Reshape the input cell array into a 1xm cell array of 1x(n^2) arrays
reshapedCellArray = reshape(inputCellArray', 1, []);
% Use cellfun to reshape each element in the reshapedCellArray into a 2x2 array
outputCellArray = cellfun(@(x) reshape(x, n, []), reshapedCellArray, 'UniformOutput', false);
% Display the resulting 1xm cell array of nxn arrays
disp(outputCellArray);
% Print the values of each 2x2 array
for i = 1:numel(outputCellArray)
fprintf('Cell %d:\n', i);
disp(outputCellArray{i});
end
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