How to create a long matrix rapidly

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Sergio
Sergio 2024-1-17
编辑： Dyuman Joshi 2024-1-17
I would like to create the given matrix
0 1 1 1 1 1 1 1 1 1
1 0 1 1 1 1 1 1 1 1
1 1 0 1 1 1 1 1 1 1
1 1 1 0 1 1 1 1 1 1
1 1 1 1 0 1 1 1 1 1
1 1 1 1 1 0 1 1 1 1
1 1 1 1 1 1 0 1 1 1
1 1 1 1 1 1 1 0 1 1
1 1 1 1 1 1 1 1 0 1
1 1 1 1 1 1 1 1 1 0
I thought of using the command "zeros" for the diagonal, and then use "ones", but "ones" does not exist.
For instance:
m=[0 ones(1,9);0 ones(0,9)....]
But that won't work.
How can I make such a matrix with such "condensed" commands instead of writing it out completely?
Thanks

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采纳的回答

Mann Baidi
Mann Baidi 2024-1-17
编辑：Mann Baidi 2024-1-17
Ran in:
Hi,
Assuming you would like to create a diagonal matrix with the diagonal as '0' and rest elements as '1'.
You can try the following code:
x=~diag(ones(10,1))
x = 10×10 logical array
0 1 1 1 1 1 1 1 1 1 1 0 1 1 1 1 1 1 1 1 1 1 0 1 1 1 1 1 1 1 1 1 1 0 1 1 1 1 1 1 1 1 1 1 0 1 1 1 1 1 1 1 1 1 1 0 1 1 1 1 1 1 1 1 1 1 0 1 1 1 1 1 1 1 1 1 1 0 1 1 1 1 1 1 1 1 1 1 0 1 1 1 1 1 1 1 1 1 1 0
For more information on "diag" function, you can refer to the link below:
https://www.mathworks.com/help/matlab/ref/diag.html
Hope this will help in resolving the query!

更多回答（1 个）

Dyuman Joshi
Dyuman Joshi 2024-1-17
编辑：Dyuman Joshi 2024-1-17
Ran in:
ones does exist, but using eye would be easier and faster here -
n = 10;
x = 1 - eye(n)
x = 10×10
0 1 1 1 1 1 1 1 1 1 1 0 1 1 1 1 1 1 1 1 1 1 0 1 1 1 1 1 1 1 1 1 1 0 1 1 1 1 1 1 1 1 1 1 0 1 1 1 1 1 1 1 1 1 1 0 1 1 1 1 1 1 1 1 1 1 0 1 1 1 1 1 1 1 1 1 1 0 1 1 1 1 1 1 1 1 1 1 0 1 1 1 1 1 1 1 1 1 1 0

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