Create a loop with doubling the previous number minus 1

Question

Sergio 2024-1-17

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/2070991-create-a-loop-with-doubling-the-previous-number-minus-1

评论： Sergio 2024-1-17

采纳的回答： Hassaan

在 MATLAB Online 中打开

Hi, I have to make this loop:

2

3

5

9

17

33

65

which is the first number multiplied by 2 and subtract 1, then double the outcome of that, and subtract 1 and so on, until 66.

I made the following, however it outputs an addition instead of a multiplication of the previous number. How can I instruct this simple command to multiply by two and subtract 1 to the previous number, and stop at 66?

Thanks

for i = 2:3:66
    
    fprintf('%d ',i)
    
end

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Answer 1

Hassaan 2024-1-17

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https://ww2.mathworks.cn/matlabcentral/answers/2070991-create-a-loop-with-doubling-the-previous-number-minus-1#answer_1391576

在 MATLAB Online 中打开

% Initialize the starting number
number = 2;
% Loop until the number exceeds 66
while number <= 66
    disp(number);
    number = number * 2 - 1;  % Multiply by 2 and subtract 1
end
     2

     3

     5

     9

    17

    33

    65

When you run this MATLAB script, it will display the sequence of numbers as per your specified rule, stopping when the next number would exceed 66.

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Answer 2

Dyuman Joshi 2024-1-17

1
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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/2070991-create-a-loop-with-doubling-the-previous-number-minus-1#answer_1391566

编辑：Dyuman Joshi 2024-1-17

在 MATLAB Online 中打开

Use a while loop and perform the operation in each iteration -

%Starting value
x = 2;
%Run the loop till the value of x is less than 66
while x<66
    
    %Display the value first
    disp(x)
    
    %Modify the value as required and re-assign it to x
    x = 2*x-1;
end
     2

     3

     5

     9

    17

    33

    65