Create a loop with doubling the previous number minus 1

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Sergio
Sergio 2024-1-17
评论： Sergio 2024-1-17
Hi, I have to make this loop:
2
3
5
9
17
33
65
which is the first number multiplied by 2 and subtract 1, then double the outcome of that, and subtract 1 and so on, until 66.
I made the following, however it outputs an addition instead of a multiplication of the previous number. How can I instruct this simple command to multiply by two and subtract 1 to the previous number, and stop at 66?
Thanks
for i = 2:3:66
fprintf('%d ',i)
end

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采纳的回答

Hassaan
Hassaan 2024-1-17
Ran in:
% Initialize the starting number
number = 2;
% Loop until the number exceeds 66
while number <= 66
disp(number);
number = number * 2 - 1; % Multiply by 2 and subtract 1
end
2 3 5 9 17 33 65
When you run this MATLAB script, it will display the sequence of numbers as per your specified rule, stopping when the next number would exceed 66.
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更多回答（1 个）

Dyuman Joshi
Dyuman Joshi 2024-1-17
编辑：Dyuman Joshi 2024-1-17
Ran in:
Use a while loop and perform the operation in each iteration -
%Starting value
x = 2;
%Run the loop till the value of x is less than 66
while x<66
%Display the value first
disp(x)
%Modify the value as required and re-assign it to x
x = 2*x-1;
end
2 3 5 9 17 33 65
If you are new to MATLAB, I suggest you take the free MATLAB Onramp tutorial to learn the syntax and essentials of MATLAB.

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