Why is not working to use listbox in my case?

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Muazma Ali
Muazma Ali 2024-1-21
评论： Voss 2024-1-28
The problem :
This is a much much simpler version of my app three that I have called for tester_app_3.
When I write disp(app.error) before if app.error==1 in tester_app_3, it does not give me the right value though it is set to be right in the functions. The value of error is just set in the combinations’s functions CaCl2_MgCl2_ZnBr2 and NaCl2_KCl_ZnBr. The other functions just compute some other values
In other words the program is not going further to the combinations I chose. Thats why it gives me the value of app.error to be ==0
I have called the simpler version of my app3 as tester_app_3, reduced the app to be much smaller than it was by removing many functions from CaCl2_ MgCl2_ ZnBr2 and NaCl_KCl_ZnBr2 and letting the smaller functions remain a part of the functions. The only big functions that I have included are the two combinations functions CaCl2_ MgCl2_ ZnBr2 and NaCl_KCl_ZnBr2 and beregn_ionic_strength_best_salts_NaCl_KCl_ZnBr2 and beregn_ionic_strength_best_salts_CaCl2_MgCl2_ZnBr .
ONLY THE CaCl2_ MgCl2_ ZnBr2 and NaCl_KCl_ZnBr2 are relevant for the problem ( I had to adjust the code within these functions so that I didnt need to attach too many functions :).
Kindly help me with my problem.
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Muazma Ali
Muazma Ali 2024-1-28
@Voss I think you have misunderstood a little bit; I placed disp (app.error) statement after the if statement for CaCl2 MgCl2 and ZnBr2 and not after NaCl KCl ZnBr2 , thats why the value of disp(app.error ) must be 1 , when I dont chose the first combination of salts..and it is not that what the app is giving me..
Voss
Voss 2024-1-28
Ran in:
You think that you have written the program so that "the value of disp(app.error ) must be 1 , when I dont chose the first combination of salts", but that's not what the program is doing.
As I explained before, when index is [1 4 6], then the following line gives app.idx = [1 2 3]
app.idx = find(index);
In fact a selection of any three salts gives app.idx = [1 2 3]. Look:
find([1 4 6])
ans = 1×3
1 2 3
find([2 7 8])
ans = 1×3
1 2 3
find([99 100001 1823746])
ans = 1×3
1 2 3
Sounds like you mean to simply do:
app.idx = index;
instead of using find there.

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