How to split array into sub arrays?

a = [1 3 5 8 11 12 15 17 18 19 20 21 24 29 31 32 33 34 35 36 38 39 69].';
%bin the data into groups of 10
k = findgroups(floor((a-1)/10));
z = accumarray(k, a, [], @(x) {x.'})
z = 5×1 cell array
    {[                1 3 5 8]}
    {[   11 12 15 17 18 19 20]}
    {[               21 24 29]}
    {[31 32 33 34 35 36 38 39]}
    {[                     69]}

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Answer 2

Matt J 2024-1-30

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https://ww2.mathworks.cn/matlabcentral/answers/2076241-how-to-split-array-into-sub-arrays#answer_1400086

编辑：Matt J 2024-2-19

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a = [1 3 5 8 11 12 15 17 18 19 20 21 24 29 31 32 33 34 35 36 38 39];
G=findgroups(discretize(a,[0:10:max(a)+10],'Include','right'));
z=splitapply(@(x){x}, a, G)
z = 1x4 cell array
    {[1 3 5 8]}    {[11 12 15 17 18 19 20]}    {[21 24 29]}    {[31 32 33 34 35 36 38 39]}

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Dyuman Joshi 2024-2-19

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splitapply() won't work if there is a gap in the data -

a = [1 3 5 8 11 12 15 17 18 19 20 21 24 29 31 32 33 34 35 36 38 39 69];
G=discretize(a,[0:10:max(a)+10],'Include','right');
z=splitapply(@(x){x}, a, G)
Error using splitapply
For N groups, every integer between 1 and N must occur at least once in the vector of group numbers.

Matt J 2024-2-19

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Small modification,

a = [1 3 5 8 11 12 15 17 18 19 20 21 24 29 31 32 33 34 35 36 38 39 69];
G=findgroups(discretize(a,[0:10:max(a)+10],'Include','right'));
z=splitapply(@(x){x}, a, G)
z = 1x5 cell array
    {[1 3 5 8]}    {[11 12 15 17 18 19 20]}    {[21 24 29]}    {[31 32 33 34 35 36 38 39]}    {[69]}