0 个投票

I am trying to sort some positive values from one array and finding the index of that.
Omega=[1.528 -1.528 0.792 -0.792];
[NN,ind]=sort(Omega(Omega>=0));
Answer:
NN=[0.792 1.528]
but
ind=[2,1] is coming which is wrong. It should ind=[3,1].
Please help regarding this.

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Dyuman Joshi
Dyuman Joshi 2024-2-1
编辑：Dyuman Joshi 2024-2-1
Ran in:

1 个投票

Ran in:
"ind=[2,1] is coming which is wrong."
It is correct.
The input to sort() only has 2 elements, so the expectation to get [3 1] as the output is misplaced -
Omega=[1.528 -1.528 0.792 -0.792];
Omega(Omega>=0)
ans = 1×2
1.5280 0.7920
I assume you want to get the indices of these particular values from the original array, in that case, try this -
NN=sort(Omega(Omega>=0))
NN = 1×2
0.7920 1.5280
[~,idx] = ismember(NN,Omega)
idx = 1×2
3 1
Ideally, you should use ismembertol to compare floating point numbers.
However, the values here are obtained directly from the original array via indexing, so ismember() works here.

更多回答（1 个）

VBBV
VBBV 2024-2-1
移动：Dyuman Joshi 2024-2-1
Ran in:

2 个投票

Ran in:
Here is another way to get the indices without overhead of using ismember function
Omega=[1.528 -1.528 0.792 -0.792];
[NN,ind]=sort(Omega)
NN = 1×4
-1.5280 -0.7920 0.7920 1.5280
ind = 1×4
2 4 3 1
ind(NN>0)
ans = 1×2
3 1

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