How to do this below?
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Suppose you have a binary sequence:
a = [0 0 1 1 1 0 0 1 1 1 1 0 0 0];
And, how can you abtain a sequence b from a?
b = [0 0 3 0 0 0 0 4 0 0 0 0 0 0];
That is, place the sum of the consequtive ones at the first location of the consecutive ones.
And, make zeros for all the other locations of ones.
Thank you,
采纳的回答
One way:
a = [0 0 1 1 1 0 0 1 1 1 1 0 0 0]
b = zeros(1,numel(a));
s_idx = strfind([0 a],[0 1]);
e_idx = strfind([a 0],[1 0]);
b(s_idx) = e_idx-s_idx+1;
b
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