How to do this below?

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Mibang
Mibang 2024-2-6
评论: Voss 2024-2-6
Suppose you have a binary sequence:
a = [0 0 1 1 1 0 0 1 1 1 1 0 0 0];
And, how can you abtain a sequence b from a?
b = [0 0 3 0 0 0 0 4 0 0 0 0 0 0];
That is, place the sum of the consequtive ones at the first location of the consecutive ones.
And, make zeros for all the other locations of ones.
Thank you,

采纳的回答

Voss
Voss 2024-2-6
One way:
a = [0 0 1 1 1 0 0 1 1 1 1 0 0 0]
a = 1x14
0 0 1 1 1 0 0 1 1 1 1 0 0 0
b = zeros(1,numel(a));
s_idx = strfind([0 a],[0 1]);
e_idx = strfind([a 0],[1 0]);
b(s_idx) = e_idx-s_idx+1;
b
b = 1x14
0 0 3 0 0 0 0 4 0 0 0 0 0 0

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