matrix convertion needs modification

I want to create a matrix with entries -1, 0, and 1 but it gives only -1 and 1, how to adjust
x = [9 3.6 9; 11 3.6 9; 9 4.4 9; 11 4.4 9; 9 3.6 11; 11 3.6 11;9 4.4 11; 11 4.4 11];
% convertion to -1, 0, and 1
V = ( x(:,1) - min(x(:,1)) )/(range(x(:,1))/2) - 1; %% This line needs some modifications
% NOW convert to MATRIX (-1. 0, and 1)
% Below lines also need some modifications
X = [(x(:,1) - min(x(:,1)))/1 - 1 (x(:,2) - min(x(:,2)))/0.4 - 1 (x(:,3) - min(x(:,3)))/1 - 1]
X = 8×3
-1.0000 -1.0000 -1.0000 1.0000 -1.0000 -1.0000 -1.0000 1.0000 -1.0000 1.0000 1.0000 -1.0000 -1.0000 -1.0000 1.0000 1.0000 -1.0000 1.0000 -1.0000 1.0000 1.0000 1.0000 1.0000 1.0000

3 个评论

What value/s (or rows of values) should be mapped to zero?
Or more generally, what values should be mapped to -1, 0, 1 ?
Please explain what you are trying to achieve!
like the output of,
dBB = bbdesign(3)
%% Can be found in https://in.mathworks.com/help/stats/bbdesign.html

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 采纳的回答

Perhaps this is what you had in mind?
x = [9 3.6 9; 11 3.6 9; 9 4.4 9; 11 4.4 9; 9 3.6 11; 11 3.6 11;9 4.4 11; 11 4.4 11];
X=rescale(x,-1,1,InputMin=min(x,[],2), InputMax=max(x,[],2) )
X = 8×3
1.0000 -1.0000 1.0000 1.0000 -1.0000 0.4595 1.0000 -1.0000 1.0000 1.0000 -1.0000 0.3939 0.4595 -1.0000 1.0000 1.0000 -1.0000 1.0000 0.3939 -1.0000 1.0000 1.0000 -1.0000 1.0000
X(abs(X)<1)=0
X = 8×3
1 -1 1 0 -1 0 1 -1 1 1 -1 0 0 -1 0 0 -1 0 0 -1 1 1 -1 1

4 个评论

looks right Matt, Thanks
I will check & Implement.
Dear Matt J
Your idea needs some modification for the following work, Please get into:
('0' is not coming)
P = [T.p1 T.p2 T.p3]; x = P;
X = rescale( x,-1,1,InputMin = min(x,[],2), InputMax = max(x,[],2) );
X(abs(X)<1) = 0
Here is the answer (attached pdf) to match the output.
Dear Matt
Why here is an option "Moved"? I didnot get that.

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