Put the separator every thousands
显示 更早的评论
T=100000000;
T1 = regexprep(string(T),'(\d+)(\d{3})$',"$1'$2")
I would like to have the thousands separator for every 1000
the correct result would be:
1'000'000'000
2 个评论
"the correct result would be: 1'000'000'000"
Why should the "correct result" be one billion when the input value is only one hundred million?
100000000 % your input value
1000000000 % your "correct result" with quotes removed
Your "correct result" is ten times larger than the input value: is that intentional or is it ... incorrect ?
shamal
2024-2-10
采纳的回答
Here are some more interesting testcases (with both one hundred million as well as one billion):
S = ["100000000";"1000000000";"123456789.123456789";"-123456789";"0";pi;"1e23456"]
S = regexprep(S,'(?<!(\.|[eE][-+]?)\d*)\d{1,3}(?=(\d{3})+(e|E|\.|\>))', '$&,')
更多回答（1 个）
Image Analyst
2024-2-10
0 个投票
I use the attached function I wrote. Adapt as needed, like change commas to apostrophes if you want.
2 个评论
CommaFormat('-123456') % ouch
Image Analyst
2024-2-11
@Stephen23 thanks for pointing that out. I've corrected it to properly handle cases where the input is negative or a string or a character array instead of a number (double, etc.). New code is attached.
It's definitely more lines than your one liner regexp though. However I'm not as adept with regexp as you -- I never would have figured out that cryptic sequence of regexp characters as you did.
类别
在 帮助中心 和 File Exchange 中查找有关 Characters and Strings 的更多信息
Translated by 
